Ask question

Ask question

All categories

antoniya [11.8K]

2 years ago

9

S = AD/AT Solve for "AD"

1 answer:

morpeh [17]2 years ago

8 0

Explanation:

AD=S×AT

after cross multiplying

You might be interested in

Which type of map would you most likely use to locate mineral deposits? A. topographic B. geologic C. satellite D. hazard

qwelly [4]

I think you would be using a topographic Map, So the answer should be A

3 0

2 years ago

What is the calculation for elastic potential?

grin007 [14]

Elastic potential energy is equal to the force times the distance of movement. Elastic potential energy = force x distance of displacement. Because the force is = spring constant x displacement, then the Elastic potential energy = spring constant x displacement squared.

3 0

2 years ago

A stationary siren emits sound of frequency 1000 Hz and wavelength 0.343 m. An observer who is moving toward the siren will meas

Ainat [17]

Answer:

f>1000Hz and wavelength=0.343 m

Explanation:

We are given that

Frequency of stationary siren,f=1000 Hz

Wavelength of stationary sound, $\lambda=0.343 m$

When a observer is moving towards the siren then the frequency increases.

Therefore,an observer who is moving towards the siren measure a frequency >1000 Hz.

The wavelength depends upon the speed of source.

But we are given that siren is stationary.

Therefore, source is not moving and then the wavelength remains same.

f>1000Hz and wavelength=0.343 m

4 0

2 years ago

Two spectators at a soccer game see, and a moment later hear, the ball being kicked on the playing field. The time delay for the

WINSTONCH [101]

Answer:

a)188.65m

b)154.35m

c)243.7m

Explanation:

Given data:

$t_A=0.55s$

$t_B=0.45s$

(a) The distance from the kicker to each of the 2 spectators is given by:

$d_A=v \times t_A$

where,

v= speed of sound

$t_A$ =time taken for the sound waves to reach the ears

$d_A=343\times 0.55=188.65$ m

(b) $d_B=v \times t_B$

where,

v= speed of sound

$t_B$ =time taken for the sound waves to reach the ears

$d_B=343\times 0.45=154.35m$

(c)As the angle b/w slight lines from the two spectators to the player is right angle,

hypotenuse=the distance b/w 2 spectators

and, the slight lines are the other 2 lines

$D^2=d_A^2+d_B^2\\D=\sqrt{188.65^2+154.35^2} \\D= 243.7m$

5 0

2 years ago

Tyyyyyyyyyyyyyyyyyyyyyyyy

Aliun [14]

Answer:

hub9hybygbgybgybgygybsbgydgbydxbgbyxdgbyxdyggdxygbyxdgybzgbydbgyzsbgydgbyzdgxbybgydzs

Explanation:

4 0

2 years ago

Read 2 more answers