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shtirl [24]
2 years ago
10

How do I calculate velocity

Physics
1 answer:
Jobisdone [24]2 years ago
5 0

Answer: See photo

Explanation: There are a couple of ways to use velocity in an equation in the photo.

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A point charge q1 = -5.7 μC is located at the center of a thick conducting spherical shell of inner radius a = 7.4 cm and outer
olga55 [171]

Answer: a) see attach file; b) E=0;  c)E=-1.65* 10^6 N/C

Explanation: In order to solve this problem we have to use the gaussian law which is given by:

∫E*dr=Q inside/εo

E for r=8 cm is located inside the conducting shell so E=0.

For r=13 cm we have to use above gaussian law considering the total charge inside a gaussian surface with radius equal to 0.13 m. ( see attach)

4 0
2 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
NemiM [27]

Answer:

their final velocity is 0.091 m/s

Explanation:

Given;

mass of the first train, m₁ = 138,000 kg

mass of the second train, m₂ = 123,000 kg

initial velocity of the first train, u₁ = 0.288 m/s

initial velocity of the seocnd train, u₂ = -0.131 m/s (opposite direction to the first)

Let their common final velocity after been coupled = v

Apply the principle of conservation of linear momentum;

m₁u₁  +  m₂u₂ = v(m₁  +  m₂)

(138,000 x 0.288)    +    (-0.131 x 123,000)   =   v(138,000 + 123,000)

39,744   -   16,113   =  v(261,000)

23,631 = v(261,000)

v = 23,631 / 261,000

v = 0.091 m/s

Therefore, their final velocity is 0.091 m/s

5 0
2 years ago
PLEASE HELP WITH ONE QUESTION!
nata0808 [166]
I think it is -3.99 x 102 j
6 0
3 years ago
A car goes from point A to point B, five miles away and then returns to point A. The car is going 15 mph.
slavikrds [6]
B will be your answer hope this helped
8 0
2 years ago
Two vectors are being added, one at an angle of 20.0 , and the other at 80.0. The only thing you know about the magnitudes is th
postnew [5]

Answer:a

Explanation: they are all positive

4 0
2 years ago
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