Answer:
(a) 5.056 x 10^-14 N
(b) 5.056 x 10^-14 N
Explanation:
X component of velocity of electron is 1.6 × 10^6 m/s
Y component of velocity of electron is 2.4 × 10^6 m/s
X component of magnetic field is 0.025 T
Y component of magnetic field is -0.16 T
charge on electron, q = - 1.6 x 10^-19 C
Write the velocity and magnetic field in the vector forms.
The force on the charge particle when it is moving in the magnetic field is given by
(a) Force on electron is given by
Magnitude of force is 5.056 x 10^-14 N.
(b) Force on a proton is given by
Magnitude of force is 5.056 x 10^-14 N.
Thus, the magnitude of force remains same but the direction of force is opposite to each other.
Explanation:
Answer:
When a positive charged object is placed near a conductor electrons are attracted the the object. ... When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side. As you know, electrons are always moving. They spin very quickly around the nucleus of an atom. As the electrons zip around, they can move in any direction, as long as they stay in their shell.
Answer:
This experiment lets you repeat Galileo's experiment in a vacuum. The free fall of a coin and feather are compared, first in a tube full of air and then in a vacuum. With air resistance, the feathers fall more slowly. In a vacuum, the objects fall at the same rate independent of their respective masses.
Answer:
I = 0.75 A
Explanation:
The question is not to calculate the resistance, but to calculate the current. (The resistance is already given by the value of 2 Ohm).
U = I * R
I = U / R
with U = 1.5 V and R = 2 Ohm
I = 1.5 / 2
I = 0.75 A
