The periodic table<span>, and its respective </span>melting<span> and </span>boiling points<span>. ... </span>Chemistry.2<span> The student </span>will <span>investigate and understand that the placement of elements ... </span>Families/groups<span> ... As </span>you<span> analyze </span>your <span>graph, try to </span>answer<span> the </span>following questions<span>: ... </span>period<span>. How </span>would you describe<span> the </span>trend<span> in </span>boiling point<span> as the atomic number ...</span>
Answer:
CCl2=CCl2
Explanation:
Recall that the individual dipole moments in a symmetrical molecule cancel out each other thereby making the overall molecule to be non polar.
CCl2=CCl2 contain individual polar bonds but the molecule is highly symmetrical thus its dipole cancel out and the molecule has no overall dipole moment, hence CCl2=CCl2 has a dipole moment of zero .
The answer is A how it react with other chemicals
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They move like waves since they're such a small particle
Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,
Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 %
</u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>
