Answer:
Hence the correct option is an option (b) Sr4, Cl,Br−,Na+.
Explanation:
Bromine and chlorine belong to an equivalent group. As we go down the group the dimensions increases which too there's a charge on the bromine atom. therefore the size of the Br- is going to be larger in comparison to the chlorine atom.
Sr atom is within the second group, and also it's below the above-mentioned atoms.so Sr is going to be the larger one among all the atoms.
Sodium and chlorine belong to an equivalent period .size decrease from left to right. but due to the charge on sodium its size decreases and there's an opportunity that Na+ size could be adequate for Cl.
Here we finally assume that two atoms are of an equivalent size (Na+ and Cl) which are less in size compared to the opposite two(Sr and Br-) during which one is greater (Sr)and the opposite is smaller(Br-).
Answer:
Explanation:
Sn(WC)2
if it is tungsten carbide this should be correct but there are many versions of carbide
Sn(MC2)2
could also be possible
the 2 next to MC should be a subscript
Between 23 and 87%
Sorry if I’m wrong
Carbon dioxide (CO2)
Argon (Ar)
Hydrogen (H)
Helium (He)
Density = mass/volume = 800/200 =4 g/cm^3
