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deff fn [24]
3 years ago
12

The 1-hour standard for NO2 from the NAAQS is 100 ppb NO2. Each breath you take is approximately 1 L of air. Assuming the air yo

u breathe is at the 1 hour standard limit for NO2: a. How many grams of NO2 do you take in with each breath? b. How many molecules of NO2 do you take in with each breath? Use formula found in the front cover of APCE to convert: (assume the air is 25 C and 1 atm) lppm - MWmolecuie)lg /m3.

Engineering
1 answer:
lara [203]3 years ago
8 0

Answer:

attached below

Explanation:

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Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 1.119\times 10^{-7}

6 0
4 years ago
How can pavement markings indicate that you are driving in the right direction?
Ann [662]

Answer:

There is a yellow line on your left and a white line on your right.

Explanation:

The yellow line between the roads separate the oncoming traffic lane, so the drivers won't get confused. Since the driver is on the right side of the road, the yellow line would be on their left, since the middle line (yellow line) is in the middle of the road.

6 0
2 years ago
9 Consider fully developed conditions in a circular tube with constant surface temperature Ts Tm. Determine whether a small- or
mojhsa [17]

Answer:

Hello your question is incomplete attached below is the complete question

answer:

Considering Laminar flow

Q ( heat )  will be independent of diameter

Considering Turbulent flow

The heat transfer will increase with decreasing "dia" for the turbulent

heat transfer = f(d^-0.8 )

Explanation:

attached below is the detailed solution

Considering Laminar flow

Q ( heat )  will be independent of diameter

Considering Turbulent flow

The heat transfer will increase with decreasing "dia" for the turbulent

heat transfer = f(d^-0.8 )

6 0
3 years ago
A 1 m wide continuous footing is designed to support an axial column load of 250 kN per meter of wall length. The footing is pla
creativ13 [48]

Answer:

correct option is (A) 0.5

Explanation:

given data

axial column load = 250 kN per meter

footing placed =  0.5 m

cohesion = 25 kPa

internal friction angle =  5°

solution

we know angle of internal friction is 5° that is near to 0°

so it means the soil is almost cohesive soil.

and for  a pure cohesive soil

N_{\gamma } = 0

and we know formula for N_{\gamma } is

N_{\gamma } = (Nq - 1 ) × tan(Ф)   ..................1

so here Ф is very less  N_{\gamma } should be nearest to zero

and its value can be 0.5

so correct option is (A) 0.5

7 0
4 years ago
The link acts as part of the elevator control for a small airplane. If the attached aluminum tube has an inner diameter of 25 mm
aksik [14]

Answer:

Tmax=14.5MPa

Tmin=10.3MPa

Explanation:

T = 600 * 0.15 = 90N.m

T_max =\frac{T_c}{j}  = \frac{x}{y}  = \frac{90 \times 0.0175}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}

=14.5MPa

T_{min} =\frac{T_c}{j}  = \frac{x}{y}  = \frac{90 \times 0.0125}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}

=10.3MPa

7 0
3 years ago
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