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3 years ago

If you purchased 2.31 μCi of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?

Chemistry

1 answer:

nikklg [1K]3 years ago

3 0

Answer:

8.547 x 10⁴disintegrations per second

Explanation:

To calculate the disintegrations per second as -

Given ,

2.31 μCi of sulfur -35 .

Since ,

1 Ci = 3.7 * 10 ¹⁰ Bq

1 μCi = 10 ⁻⁶ Ci

Hence ,

conversation is done as follows -

2.31 ( 1 * 10⁻⁶) * ( 3.7 * 10¹⁰)

= 8.547 x 10⁴

Hence ,

8.547 x 10⁴disintegrations per second , the sample undergo for it to be brand new .

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13.How many grams of phosphorus (P4) are needed to completely consume 79.2 L of chlorine gas according to the following reaction

BabaBlast [244]

Answer:

73.2g

Explanation:

The reaction expression is given as:

P₄ + 6Cl₂ → 4PCl₃

Given parameters:

Volume of chlorine gas = 79.2L

Unknown:

Mass of Phosphorus needed = ?

Solution:

To solve this problem, let us find the number of moles of the chlorine gas.

Since the condition of the reaction is at STP;

22.4L of gas is contained in 1 mole

79.2L of chlorine gas will contain $\frac{79.2}{22.4}$ = 3.54mole

From the reaction expression;

6 moles of chlorine gas will react with 1 mole of P₄

3.54 mole of chlorine gas will completely react with $\frac{3.54}{6}$ = 0.59mole of P₄

Mass of P₄ = number of moles x molar mass

Molar mass of P₄ = 4 x 31 = 124g/mol

Mass of P₄ = 0.59 x 124 = 73.2g

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3 years ago

Factors affecting movement of colored pigments in a paper chromatography

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solubility of the solvent,

molecular size of the solute

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2 years ago

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The rate constant for a certain reaction is k = 6.50×10−3 s−1 . If the initial reactant concentration was 0.600 M, what will the

Kamila [148]

Answer: 1.037M

Explanation:

Since the rate constant unit is per seconds, therefore it is a first order reaction.

First order reaction equation is given as

InA= -kt +InAo

Where,Ao is the initial concentration of reactant =0.600M

A is the concentration of reactant at a specifies time t=3×60=180s

and k is the rate constant

InA = -6.50×10^-3 ×180 +In(0.6)

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3 years ago

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julia-pushkina [17]

Explanation:

As per Brønsted-Lowry concept of acids and bases, chemical species which donate proton are called Brønsted-Lowry acids.

The chemical species which accept proton are called Brønsted-Lowry base.

(a) $HNO_3 + H_2O \rightarrow H_3O^+ + NO_3^-$

$HNO_3$ is Bronsted lowry acid and $NO_3^-$ is its conjugate base.

$H_2O$ is Bronsted lowry base and $H_3O^+$ is its conjugate acid.

(b)

$CN^- + H_2O \rightarrow HCN + OH^-$

$CN^-$ is Bronsted lowry base and HCN is its conjugate acid.

$H_2O$ is Bronsted lowry acid and $OH^-$ is its conjugate base.

(c)

$H_2SO_4 + Cl^- \rightarrow HCl + HSO_4^-$

$H_2SO_4$ is Bronsted lowry acid and $HSO_4^-$ is its conjugate base.

Cl^- is Bronsted lowry base and HCl is its conjugate acid.

(d)

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$HSO_4^-$ is Bronsted lowry acid and $SO_4^{2-}$ is its conjugate base.

OH^- is Bronsted lowry base and $H_2O$ is its conjugate acid.

(e)

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$O_{2-}$ is Bronsted lowry base and OH- is its conjugate acid.

$H_2O$ is Bronsted lowry acid and OH- is its conjugate base.

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3 years ago

I need help idk how to do the predicting product

kaheart [24]

Answer:

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Explanation:

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3 years ago

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