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vovikov84 [41]
3 years ago
11

If you purchased 2.31 μCi of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?

Chemistry
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

8.547 x 10⁴disintegrations per second

Explanation:

To calculate the disintegrations per second as -

Given ,

2.31 μCi of sulfur  -35 .

Since ,

1 Ci = 3.7 * 10 ¹⁰ Bq

1 μCi = 10 ⁻⁶ Ci

Hence ,

conversation is done as follows -

2.31 ( 1 * 10⁻⁶) * ( 3.7 * 10¹⁰)

= 8.547 x 10⁴

Hence ,

8.547 x 10⁴disintegrations per second , the sample undergo for it to be brand new .

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3 years ago
Mass is 5 grams and the volume is 4.5 grams what is the density
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Which of the following statements holds true for a chemical change?
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6 0
3 years ago
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Hopes this helps >:D

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3 years ago
What is the radius of a hydrogen atom whose electron is bound by 0.544 ev? express your answer with the appropriate units?
insens350 [35]
First, we need to calculate the principal quantum number n for this electron, using the equation:
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3 years ago
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