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MA_775_DIABLO [31]
3 years ago
14

What tool measures mass?​

Chemistry
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

balances and scales, measurement transducers, vibrating tube sensors, Newtonian mass measurement devices and the use of gravitational interaction between objects.

Explanation:

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PLEASE HELP WITH THIS QUESITION WILL GIVE BRAINLIST 2 BEST ANSWER.
Lera25 [3.4K]

Answer: show all

Explanation:

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4 0
2 years ago
The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. Combustion of
gavmur [86]

<u>Answer:</u> The empirical formula for the given compound is C_3H_6O

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Conversion factor:  1 g = 1000 mg

Mass of CO_2=6.32mg=0.00632g

Mass of H_2O=2.58g=0.00258g

Mass of compound = 2.78 mg = 0.00278 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.00632 g of carbon dioxide, \frac{12}{44}\times 0.00632=0.00172g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.00258 g of water, \frac{2}{18}\times 0.00258=0.000286g of hydrogen will be contained.

  • Mass of oxygen in the compound = (0.00278) - (0.00172 + 0.000286) = 0.000774 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.00172g}{12g/mole}=1.43\times 10^{-4}moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.000286g}{1g/mole}=2.86\times 10^{-4}moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.000774g}{16g/mole}=4.83\times 10^{-5}moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 4.83\times 10^{-5}mol

For Carbon = \frac{1.43\times 10^{-4}}{4.83\times 10^{-5}}=2.96\approx 3

For Hydrogen  = \frac{2.86\times 10^{-4}}{4.83\times 10^{-5}}=5.92\approx 6

For Oxygen  = \frac{4.83\times 10^{-5}}{4.83\times 10^{-5}}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is C_3H_{6}O_1=C_3H_6O

3 0
3 years ago
An atom can act as a tiny magnet due to the spinning motion of charged particles called neutrons. Please select the best answer
Tatiana [17]
Falso porque los neutrones no tienen carga
7 0
3 years ago
what is a major drawback of using fossil fuels they warmn the planet they contain no greenohuse gases
Charra [1.4K]

The major drawback of fossil fuels is that they warm the planet i.e. they cause global warming.

The reaction typically gives off heat and light as well. The general equation for a complete combustion reaction is:

                                  Fuel + O2 → CO2 + H2O + ENERGY

<h3>Disadvantages of Fossil fuels</h3>

The term "fossil fuels" refers to flammable organic geologic formations, including dead organic matter that has been buried hundreds of feet beneath sediment.

  • Fossil fuel emissions include various oxides, such as carbon, nitrogen, and sulfate, which cause acid rain and harm the soil's fertility and water quality.
  • Both coal and petroleum burning discharge a significant amount of pollutants into the atmosphere, contributing to pollution levels.
  • Gases like carbon dioxide are released through the burning of fossil fuels, which aids in climate change.

To view similar questions on Fossil fuels, refer to:

brainly.com/question/14339391

#SPJ4

7 0
1 year ago
The dehydration of the alcohol functional group is a widely used reaction in organic chemistry. The mechanism is generally accep
puteri [66]

Answer:

  1. Elimination
  2. Elimination
  3. Zaitsev
  4. Zaitsev
  5. Carbocation

Explanation:

  • The mechanism is generally accepted to always operate via an ELIMINATION step-wise process.
  • The ELIMINATION mechanism process will always produce (after dehydration) a ZAITSEV style alkene as major product
  • The driving force for the production of this ZAITSEV style alkene product is generally going to be determined by stability of the CARBOCATION

Elimination mechanism is the removal of two substituents  from a molecule in either a one- or two-step mechanism

Carbocation is a molecule containing a positive charged carbon atom and three bonds

3 0
3 years ago
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