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3 years ago

Which statement best describes ionic bonding?

Physics

2 answers:

LuckyWell [14K]3 years ago

6 0

Electrons are transferred from one atom to another describes ionic bonding.

Option D

<u>Explanation</u>:

Ionic bonding requires at least one acceptor and one donor. ''Ionic bond'' is the movement of ''valence electrons'' between atoms. It gives two oppositely charged ions after taking place. The metal loses electrons and form a positive cation, and non metals gains electrons to become negative cations. Thus electron donor is a metal, and electron acceptor is usually a non metal. Thus, it is evident that in ionic bonding electrons are transferred between atoms.

FromTheMoon [43]3 years ago

4 0

D. Ionic bonding is when electrons are transferred. When they're shared, it is covalent. In order to take an electron from a full valence electeon shell, you would need a massive amount of energy.

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vesna_86 [32]

To solve the problem it is necessary to apply the definition of Newton's second Law and the definition of density.

Density means the relationship between volume and mass:

$\rho = \frac{m}{V}$

While Newton's second law expresses that force is given by

F = ma

Where,

m = mass

a= acceleration (gravity at this case)

In the case of the given data we have to,

$m_b = 3Kg$

$r = 1.5m\\V = \frac{4}{3}\pi r^3 \\V = \frac{4}{3} \pi 1.5^3\\V = 14.13m^3$

In equilibrium, the entire system is equal to zero, therefore

$\sum F = 0$

$F_g +F_h-F_b = 0$

Where,

$F_g =$ Weight of balloon

$F_h =$ Weight of helium gas

$F_b =$ Bouyant force

Then we have,

$mg+V\rho g -V\rho_a g = 0$

$\rho = \rho_0-\frac{m}{V}$

Replacing the values we have that

$\rho = 1.19kg/m^3 -\frac{3Kg}{14.13m^3}$

$\rho = 0.978kg/m^3$

Now by ideal gas law we have that

$PV=nRT$

$P\frac{\rho}{m} = nRT$

$P = \rho \frac{n}{m}RT$

But the relation \frac{n}{m} is equal to the inverse of molar mass, that is

$P = \frac{\rho}{M_0} RT$

$P = \frac{0.978kg/m^3}{0.04kg/mol}*8.314J/K.Mol * 305K$

$P = 619995.7Pa$

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5 0

3 years ago

PLEASE HELP!! WILL REWARD!!

Fudgin [204]

$velocity = \frac{displacement}{time}$

Displacement measures how far it is from the starting point and the final location, which in this case is the distance between Honolulu and Los Angeles. The difference between distance and displacement is that distance measures how far the object actually travels. For example, the airplane may not fly in a straight line and it may have detours, making the distance much greater than the displacement.

On the other hand, the plane could fly at different speeds at different periods of time. It will be so much more complicated if we have to calculate it. That's why this question only asks you to calculate the average velocity of the plane, ie. $\frac{total displacement}{total time}$

So, we have

the required average velocity = $\frac{2558}{5}$

= 511.6 miles/hour

Hope this helps!

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Keith_Richards [23]

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