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Nataly [62]
4 years ago
8

A 4 kg object is being pulled to the east by a 6 N force. What is the object's acceleration? A. 0.67 m/s², east B. 0.67 m/s², we

st C. 1.5 m/s², east D. 1.5 m/s², west
A. 0.67 m/s², east
B. 0.67 m/s², west
C. 1.5 m/s², east
D. 1.5 m/s², west
Physics
2 answers:
erastovalidia [21]4 years ago
8 0

A would be the answer to that question

ruslelena [56]4 years ago
4 0
Prob C. Not sure tho
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Pls help. This is about heat. I got the answer, just need the working
Mars2501 [29]

Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C  from 20 C

  this will take   .20 kg *    390 j /kg-C   *  80 C = <u>6240 j</u>

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take    

    .50 kg * 4182 j/kg-C  * 80 = <u>167,280 j </u>

AND you have to add enough heat to boil off  .03 kg of water:

   .03 kg * (2260000 j/kg-C )  =<u> 67,800 j</u>

<u />

Power = joules / sec =  (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>

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<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>

7 0
2 years ago
A force can exist between two charged particles or objects even if they're as small as subatomic particles. Between which of the
ASHA 777 [7]
If both particles have the SAME electrical charge, then they repel.
If they have DIFFERENT electrical charge, then they attract.

Protons have  +  charge .
Electrons have  -  charge .

So two protons (A) or two electrons (D) push apart.

One proton and one electron (C) pull together.
3 0
3 years ago
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According to the graph of displacement vs. time, what is the object's displacement at time = 60 s?
krek1111 [17]

Answer:

The straight line that is obtained, intercept it on the y-axis and the value of displacement will obtained.

Explanation:

4 0
3 years ago
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Consider the following possibilities and select the correct choice.
dezoksy [38]

Answer:

Tx not but mybe

Explanation:

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4 0
3 years ago
1. A piece of metal weighs 50.0 N in air, 36.0 N in water, and 41.0 N in an unknown
denis23 [38]

Answer:

a) 3.37 x 10^{3} kg/m^3

b) 6.42kg/m^{3}

Explanation:

a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies the mass of metal is 5kg.

Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x 10^{-4}  kg/m^{3}. So density of metal = mass of metal / volume of metal = 5 / 14 x 10^{-4}  kg/m^{3} = 3.37 x 10^{3} kg/m^3

b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/m^{3}

3 0
3 years ago
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