The current through two identical light bulbs connected in series is 0.25 A. The voltage across both bulbs is 110 V. The resista

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The current through two identical light bulbs connected in series is 0.25 A. The voltage across both bulbs is 110 V. The resista

nce of a single light bulb is The current through two identical light bulbs connected in series is 0.25 A. The voltage across both bulbs is 110 V. The resistance of a single light bulb is 22 ohms. 220 ohms. 440 ohms. 44 ohms. none of these

Physics

1 answer:

Rus_ich [418] · Answer 1 · 2023-05-31T20:14:01+03:00

The resistance of a single light bulb is 220 ohms per bulb.

Ohm's Law is a formula used to determine how voltage, current, and resistance in an electrical circuit relate to one another.

Ohm's Law (E = IR) is as basic to students of electronics as Einstein's Relativity equation (E = mc2) is to physicists.

E = I x R

The formula reads voltage = current x resistance, or V = A xΩ., or volts = amps x ohms.

110volts divided by .25amps = 440 ohms. 440 divided by 2 =220 ohms per bulb.

R = 110/(2*0.25) = 220 ohms

to learn more about Ohms law go to - brainly.com/question/14296509

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