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3 years ago

How can the effect of chromatic aberration be reduced?

2 answers:

kramer3 years ago

6 0

The answer to the question:
<span>How can the effect of chromatic aberration be reduced?
A) by using multiple lenses
B) by reducing the focal length
C) by using a larger objective lens
D) by making the telescope larger

is:
</span>B) by reducing the focal length

alexgriva [62]3 years ago

5 0

Answer:

A - by using multiple lenses

Other ways to reduce chromatic abberration is by increasing the focal length, changing the color image to black and white, using an achromatic lens etc

Explanation:

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A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.540 and

Zinaida [17]

Answer:

73.13°

Explanation:

According to snell's law,

n1sinθi = n2sinθr

n1/n2 = sinθr/sinθi

Critical angle is the angle of incidence at the denser medium when the angle of incidence at the less dense medium is 90°

This means i=C and r = 90°

The Snell's law formula will become

n1/n2 = sinC/sin90°

n2/n1 = 1/sinC

Where n1 is the refractive index of the less dense medium = 1.473

n2 is the refractive index of the denser medium = 1.540

Substituting the values in the formula,

1.540/1.473 = 1/sinC

1.045 = 1/sinC

SinC = 1/1.045

SinC = 0.957

C = sin^-1(0.957)

C = 73.13°

4 0

4 years ago

A person weighing 500 N climbs 3 m. How much power is needed to make the climb in 5 sec?

kkurt [141]

<span>work = 500*3 = 1500 J
1500J in 5 sec = 300 watts

Hope that helps:)</span>

7 0

3 years ago

Read 2 more answers

Part A

Makovka662 [10]

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

$p = mv$

Where, m = mass

v = velocity

Put the value into the formula

$p=0.0073\times0.65$

$p=0.004745\ kg m/s$

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

$p=mv$

$v=\dfrac{p}{m}$

Put the value into the formula

$v=\dfrac{3.14}{0.136}$

$v=23.0\ m/s$

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

7 0

3 years ago

A beam of light from a laser illuminates a glass how long will a short pulse of light beam take to travel the length of the glas

Eduardwww [97]

Answer:

The time of short pulse of light beam is $2.37\times10^{-9}\ sec$

Explanation:

Given that,

A beam of light from a laser illuminates a glass.

Suppose, the length of piece is $L=25.21\times10^{-2}\ m$

Index of refraction is 2.83.

We need to calculate the speed of light pulse in glass

Using formula of speed

$v=\dfrac{c}{\mu}$

Put the value into the formula

$v=\dfrac{3\times10^{8}}{2.83}$

$v=1.06\times10^{8}\ m/s$

We need to calculate the time of short pulse of light beam

Using formula of velocity

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{25.21\times10^{-2}}{1.06\times10^{8}}$

$t=2.37\times10^{-9}\ sec$

Hence, The time of short pulse of light beam is $2.37\times10^{-9}\ sec$

3 0

4 years ago

What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.

Karo-lina-s [1.5K]

The energy carried by a single photon is given by
$E=hf$
where h is the Planck's constant and f is the frequency of the photon.

The photon of our exercise has a frequency of $f=1.7 \cdot 10^{17} Hz$ , therefore its energy is
$E=hf=(6.63 \cdot 10^{-34}Js)(1.7 \cdot 10^{17} Hz)=1.1 \cdot 10^{-16} J$

3 0

3 years ago

Read 2 more answers