Answer:
17g
Explanation:
4NH3 (g) + 502 (g) –> 4NO (g) + 6H20 (g)
Mass of O2 mole = 32g
Therefore 5O2 = 160g
Mass of NH3 mole = 17g
Therefore 4NH3 = 17 x 4 =68g
Required amount of NH3 = 68 x 40/160 = 17g
PV = nRT
1.026atm * 42l = n * 0.0821L atm/mol K * 305K
n=1.72.
1.72 molecules.
<span>Hello!
We have the following data:
W (molality) = ? (in Molal)
m1 (mass of the solute) = 14.7 g
m2 (mass of the solvent) =? (in Kg)
d (</span><span>solvent density) = 1,00 g/mL
</span>V (volume of the solvent) = 150 mL
<span>The mass of the solvent will be found by the following formula
</span>
<span>
</span>
<span>
M1 (Molar mass of solute - </span>C6H12O6) = ?
C = 6*12 = 72 u
H = 12*81 = 12 u
O = 6*16 = 96 u
------------------------
M1 (Molar mass of solute - C6H12O6) = 72+12+96 = 180 g/mol
<span>Now, let's find Molality, applying the above data to the formula, let's see:
</span>
I hope this helps. =)
Answer:
The temperature at which a substance changes from the liq- uid state to the solid state is called the freezing point. The freez- ing point of the liquid state of a substance is the same temperature as the melting point of the solid state. For example, solid water melts at 0°C and liquid water freezes at 0°C.
Explanation: