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Oduvanchick [21]
3 years ago
10

Which of the following answers below is the correctly balanced half-reaction for the reduction of the SO4 ^-2 ion in acid soluti

on? The answer is C, but I don’t understand why. Thanks in advance :-)

Chemistry
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:

C

Explanation:

The oxidation number of Sulphur in SO4^2- is;

x + 4(-2) = -2

x - 8 = -2

x = -2 + 8

x = 6

Now,

the oxidation number of sulphur in H2SO3 is

2 (1) + x + 3(-2) = 0

2 + x -6 = 0

-4 + x = 0

x = 4

Hence, the oxidation number of sulphur changed from +6 to +4 which signifies  gain of two electrons as shown in option C.

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In the reaction below green chlorine gas and brown iodine chloride forms yellow iodine trichloride Cl2 (g) + ICl (l) ⇌ ICl3 (s)
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Please help! I’m on my last attempt
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A mole of Big Macs stacked would reach from the earth to the moon and back how many times?
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A mol=6.02*10^23
so
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divide both sides by 2
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825583769024485.8
about 825,583,769,024,486 times

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