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3 years ago

Velocity of sound increases on a cloudy day. Why?

2 answers:

8 0

The density of air reduces as humidity and amount of water in the air increases. The speed of sound is inversely proportional to the root of density, therefore sound travels faster on a cloudy day than on a dry day so, velocity of sound increase.

Bond [772]3 years ago

7 0

Answer:

Because there's a decrease in density.

Explanation:

For fluids, the speed of sound (Vs) is given by the relationship :

$V_{s}=\sqrt{\frac{K_{s}}{d}}$ , where:

Ks = coefficient of stiffness, the isentropic bulk modulus (or the modulus of bulk elasticity for gases).

d = density of the fluid.

As we can see, speed of sound is inversely proportional to density. If density decreases, speed of sound increases.

In a cloudy day, humidity is very high (in fact, when it rains, relative humidity is 100% (maximum) which is why the clouds can't hold any more water). Density is inversely proportional to humidity. So, in a cloudy (or highly humid) day, density decreases, causing an increment in the velocity of sound.

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The operating temperature of a tungsten filament in an incandescent light bulb is 2450 K, and its emissivity is 0.350. Find the

natulia [17]

Answer:

The value is $A = 2.80 *10^{-4} \ m^2$

Explanation:

From the question we are told that

The operating temperature is $T = 2450 \ K$

The emissivity is $e = 0.350$

The power rating is $P = 200 \ W$

Generally the area is mathematically represented as

$A = \frac{P}{ e * \sigma * T^2}$

Where $\sigma$ is the Stefan Boltzmann constant with value

$\sigma = 5.67 *10^{-8} \ W/m^2\cdot K^4$

$A = \frac{200}{0.350 * 5.67*10^{-8} * 2450^{4}}$

$A = 2.80 *10^{-4} \ m^2$

8 0

3 years ago

To balance a chemical equation we use______. -coefficients -subscripts

Vitek1552 [10]

Answer:

Coefficients

Explanation:

Coefficients are used to balance chemical equations.
According to the law of conservation of mass, the mass of the reactants in a chemical equation should be equivalent to the mass of the products.
The conservation of mass is achieved in chemical equations is achieved through balancing chemical equations.
Balancing chemical equations is a try and error of putting appropriate coefficients to the reactants or products to ensure that the number of atoms of each element are equal on the side of the reactants and that of products.

3 0

3 years ago

Consider a book that weighs 15 N at rest on a flat table. How many newtons of support does the table provide?

zysi [14]

The support force is 15 N. The net force on the book is zero.

7 0

3 years ago

I need someone that has a course hero subscription to help me I need all the pages

SVETLANKA909090 [29]

Answer:

So what's the answer???

Explanation:

8 0

3 years ago

When a voltage difference is applied to a piece of metal wire, a 5.0 mA current flows through it. If this metal wire is now repl

zheka24 [161]

Answer:

I = 21.13 mA ≈ 21 mA

Explanation:

I₁ = 5 mA

L₁ = L₂ = L

V₁ = V₂ = V

ρ₁ = 1.68*10⁻⁸ Ohm-m

ρ₂ = 1.59*10⁻⁸ Ohm-m

D₁ = D

D₂ = 2D

S₁ = 0.25*π*D²

S₂ = 0.25*π*(2*D)² = π*D²

If we apply the equation

R = ρ*L / S

where (using Ohm's Law):

R = V / I

we have

V / I = ρ*L / S

If V and L are the same

V / L = ρ*I / S

then

(V / L)₁ = (V / L)₂ ⇒ ρ₁*I₁ / S₁ = ρ₂*I₂ / S₂

S₁ = 0.25*π*D² and

S₂ = 0.25*π*(2*D)² = π*D²

we have

ρ₁*I₁ / (0.25*π*D²) = ρ₂*I₂ / (π*D²)

⇒ I₂ = 4*ρ₁*I₁ / ρ₂

⇒ I₂ = 4*1.68*10⁻⁸ Ohm-m*5 mA / 1.59*10⁻⁸ Ohm-m

⇒ I₂ = 21.13 mA

5 0

3 years ago