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3 years ago

To live deep ocean what condition do a fish need to be adapted for

Physics

1 answer:

tekilochka [14]3 years ago

7 0

High pressure
Low oxygen
Darkness

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Why do ions stick together?

melisa1 [442]

Answer:

The ions stick together because of the electrostatic attraction between ions that are near one another.Electrostatic attraction refers to the electrostatic force of long-range interaction occurring between the attractive electrostatic adsorption in aqueous solution with differently charged particles or uncharged particles.

Hope this helps!! ;)

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3 years ago

An atom that has 84 protons and 86 neutrons undergoes a reaction. At the end of the reaction, it has 82 protons and 84 neutrons.

Tju [1.3M]

Hi! the atom in this particular problem has emitted an alpha particle in a nuclear reaction.

Glad I could help, and happy learning!

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3 years ago

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A butterfly flies from the top of a tree in the center of a garden to rest on top of a red flower at the garden's edge. The tree

Zielflug [23.3K]

The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.

$x=\sqrt{(9)^2+(0.17)^2}$

$x = 9.0061 \approx 9.0 m$

Therefore the magnitude of the butterfly's displacement is 9m

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3 years ago

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The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medi

adoni [48]

Answer:

The value of new coulomb force is 1.43 N.

Explanation:

Given;

Coulomb's force in vacuum (air), $F_v$ = 10 N

dielectric constant, K = 7

The Coulomb's force between two charges separated by a distance r in a vacuum is given as;

$F_v = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2}$

The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as

$F_m = \frac{1}{4\pi K\epsilon_0} \frac{q_1q_2}{r^2}$

Take the ratio of the two forces;

$\frac{F_v}{F_m} = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2} \ \times \ \frac{4\pi K\epsilon_0 r^2}{q_1q_2} = K\\\\\frac{F_v}{F_m} = K\\\\\frac{10}{F_m} = 7\\\\F_m = \frac{10}{7} \\\\F_m = 1.43 \ N$

Therefore, the value of new coulomb force is 1.43 N.

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3 years ago

Joseph is sitting in the family van. His mother is driving him from their house to the library. Joseph waves as he passes his fr

zubka84 [21]

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