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Kamila [148]
3 years ago
5

PLZ ANSWER

Chemistry
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

B. The student should model a convex lens because it directs light toward the center of the lens.

Explanation:

Lenses are optical devices that work on the principle of refraction.

Refraction is a phenomenon of wave (such as light waves) that occurs when a ray of light crosses the interface between two mediums with different optical density: when this occurs, the ray of light bends and change speed.

In particular, there are two types of lenses:

  • Convex lenses: these lenses are curved outward at their center, therefore the rays of light coming from infinite distance (parallel to the axis) are all focused into a point of the lens, called principal focus. Therefore, a convex lens directs lights towards this point.
  • Concave lenses: these lenses are curved inward at their center, therefore the rays of light coming from infinite distance are bent away from the principal focus. Therefore, this is a diverging lens, as the rays of light do not converge.

So, the correct answer is

B. The student should model a convex lens because it directs light toward the center of the lens.

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Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
What did you include in your hypothesis? Check all that apply.
Tcecarenko [31]

The following observation would be included in a hypothesis: a connection between type of material and thermal energy transfer is developed (option C).

<h3>What is a hypothesis?</h3>

Hypothesis is a tentative conjecture explaining an observation, phenomenon or scientific problem that can be tested by further observation, investigation and/or experimentation.

The hypothesis is regarded as an educated guess because it predicts the possible outcome of an experiment.

The hypothesis is a statement that relates the independent variable of the experiment with the measured or dependent variable.

Therefore, the following observation would be included in a hypothesis: a connection between type of material and thermal energy transfer is developed.

Learn more about hypothesis at: brainly.com/question/13025783

#SPJ1

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1 year ago
How many moles of O2 is needed to form 2.19 moles of CO2 in the reaction
bagirrra123 [75]
It is always half of what the o2 is
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3 years ago
Sentences with word carcasses
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8 0
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Draw the structures of two stereoisomeric alkenes that would give 3-hexanol as the only major product of hydroboration followed
soldi70 [24.7K]

Answer:

cis-3-hexene and trans-3-hexene

Explanation:

Hydroboration oxidation is a method of preparation of alcohol from alkene.

Hydroboration follows anti-Markovnikoff rule in which alcohol group attached to less substituted carbon. Stereochemistry of the product is always syn that is H and OH attached to the same side of the double bond.

cis-3-hexene and trans-3-hexene undergoes hydroboration to form 3-hexanol.

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