b is your answers in this thread
F = m . g = 76.5 x 9..8 = 749.7
Net Force = 3225 - 749.7 = 2475.3
F = m.a
2475.3 = 76.5 a
a = 32.35
V = at + v1
V = at + 0
V = 32.35 x 0.15
V = 4.8525
Hope this helps
Answer:
<h2>1/7 kg</h2>
Explanation:
Find the diagram attached for better understanding of the question.
Given the mass of one of the blocks to be 1.0kg and accelerates downward at 3/4g.
g = acceleration due to gravity.
Let the block accelerating downward be M, mass of the other body be 'm' and the acceleration of the body M be 'a'.
M = 1.0 kg and a = 3.4g
According to newton's second law;
For body of mass m;
T - mg = ma ... (1)
For body of mass M;
Mg - T = Ma ... (2)
Adding equation 1 ad 2;
+Mg -mg = ma + Ma
Ma-Mg = -mg-ma
M(a-g) = -m(a+g)
Substituting M = 1.0 kg and a = 3/4g into the resulting equation;
3/4 g-g = -m(3/4 g+g)
3/4 g-g = -m(7/4 g)
-g/4 = -m(7/4 g)
1/4 = 7m/4
28m = 4
m = 1/7 kg
Therefore the mass of the other box is 1/7 kg
Answer:
176.44 m
Explanation:
y = (vertical vi)t + (1/2)gt^2
315 = 0 + (1/2)(9.8)t^2
t = 8.02s
x = (horizontal vi)t + (1/2)at^2
x = (22)(8.02) + 0
x = 176.44 m
Answer:
rate= 5000 m/million years
Explanation:
In order to find this rate, we must divide the number of meters it has moved into the number of years it took the plate to move that distance, so we get:
rate= 5000 m/million years.