D. Pentane. Pentane has 5 Carbon and 12 Hydrogen, like the molecule shown.
Answer:
Na2CO3 is the formula for sodium carbornate
To solve this given problem, we can use the equation below:
ΔG=ΔH - T*ΔS
We are information and values are given and can be used in solving the ΔG of this particular reaction.
ΔH=-99.84kJ
ΔS=-16.80 J/K
T=298K
ΔG=(-99.84kJ)-(298K*-16.80J/K)
ΔG=-94.83kJ
The answer for ΔG is -94.83kJ.
Answer:
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
Explanation:
First equation:
The reactants propane and water react to form the products CO and H2
C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)
Second equation:
The products CO and H2 will react
CO(g) + H2O(g) → H2(g) + CO2(g)
We should multiply the equation by 3 (to equal the products of the first equation)
3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)
Add the second to the first equation:
C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
2F⁻ → F₂ + 2e⁻
(mainly electrochemical oxidation)
