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Vesna [10]
3 years ago
11

a cyclist must travel 800 km. how many days will the trip take if the cyclist travels 8/h day at an average speed of 16km/h

Physics
2 answers:
sergey [27]3 years ago
7 0
It would b 6 days and 6 hours
You would times 16 by 8 which gives 128km a day. To find how many days you would divide 800 by how many kilometres they cover a day which is 128
So 800/128 =6.25 which converts to 6 days and 6 hours.
Orlov [11]3 years ago
7 0

Answer:at the rate of 16km/h he will travel 16*8=128km per day

800/128=6.25 days

Explanation:

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A football kick returner catches the ball just as a player from the opposing team dives to tackle him. At the time of impact, th
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The total momentum of the players after collision is 130 kgm/s.

The given parameters:

  • <em>Initial momentum of the returner, </em>P_i_1<em> = 0 kgm/s</em>
  • <em>The initial momentum of the diving player, </em>P_i_2<em> = 130 kgm/s</em>

The total momentum of the players after collision is determined by applying the principle of conservation of linear momentum as follows;

P_f = P_i_1 + P_i_2\\\\P_f = 0 + 130\\\\P_f = 130 \ kgm/s

Thus, the total momentum of the players after collision is 130 kgm/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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2 years ago
A ramp leading to the entrance of a building is inclied upward at an angle of 7 degree. A suitcase is to be pulled up the ramp b
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Explanation:

The angle of the handle relative to the horizontal is 35°.  The angle of the ramp to the horizontal is 7°.  So the angle of the handle relative to the ramp is 28°.

cos 28° = 50 / F

F = 50 / cos 28°

F = 56.6 lbs

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3 years ago
When two adjacent lights blink on and off in quick succession, we perceive a single light moving back and forth between them. th
makkiz [27]
This is called the Phi Phenomenon.
This is an illusion of movement created when two or more adjacent lights blink on and off in quick succession; when two adjacent stationary lights blink on and off in quick succession; we perceive a single light moving back and forth between them. It is an optical illusion of perceiving a series of still images, when viewed in rapid succession, as continuous motion. 
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A force of 300 N is used to stretch a horizontal spring with a 0.5 kg block attached to it by 0.5 m. The block is released from
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6 0
3 years ago
Two charged particles separated by a distance of = 3 and experienced electrostatic forces of = 60 . What would be this force if
klemol [59]

Answer: 539.4 N

Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:  

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"

What is written above is expressed mathematically as follows:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}} (1)

Where:

F_{E}=60 N  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1} and q_{2} are the electric charges

d=3 m is the separation distance between the charges  

Then:

60 N= 8.99(10)^{9} Nm^{2}/C^{2}\frac{q_{1}.q_{2}}{(3 m)^{2}} (2)

Isolating q_{1} and q_{2}:

q_{1}q_{2}=6(10)^{-8} C^{2} (3)

Now, if we keep the same charges but we decrease the distance to d_{1}=1 m, (1) is rewritten as:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{6(10)^{-8} C^{2}}{(1 m)^{2}} (4)

Then, the new electrostatic force will be:

F_{E}= 539.4 N (5) As we can see, the electrostatic force is increased when we decrease the distance between the charges.

4 0
3 years ago
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