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MrRissso [65]
3 years ago
5

Which of the following descriptions of the storage requirements for alkali metals is the most accurate? Select the correct answe

r below: A. They must be kept separate from moisture and oxygen. B. They must be kept separate from other alkali metals. C. They must be kept separate from non-alkali metals. D. They must be kept separate from mineral oil.
Chemistry
1 answer:
elena55 [62]3 years ago
7 0

Answer:

A. They must be kept separate from moisture and oxygen

Explanation:

Alkali metals refers to a group of chemical elements in the periodic table. It is the common name given to Group 1 elements (excluding hydrogen). They are generally metallic in nature with physical properties like shining lustre, silvery in appearance etc. Alkali metals include lithium, Pottasium, Sodium, Rubidium etc.

One important chemical property of alkali metals is their high reactivity i.e. they tend to react quickly with other substances. For example, alkali metals react vigorously with water to form hydroxides. They also react with oxygen to form oxides. Due to this highly reactive properties, they are kept or stored away from moisture (water) and oxygen (present in air).

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The table shows the chemical formulas for four substances. Which substance have the same numbers of carbo atoms?
mr_godi [17]

Answer:

Explanation:

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6 0
3 years ago
How many kilojoules of heat are required to vaporize 50.0 g of ethanol (MM = 46.07 g). Its molar heat of vaporization is 43.5 kJ
guajiro [1.7K]

Answer:

ΔH = 41.7 kj

Given data:

Mass of ethanol = 50 g

Heat required to vaporize = ?

Boiling point of ethanol = 78.3°C

Molar heat of vaporization = 38.6 kj/mol

Solution:

First of all we will calculate the number of moles.

Number of moles = mass / molar mass

Number of moles = 50 g/ 46.07 g/mol

Number of moles = 1.08 mol

ΔH = 38.6 kj/mol ×1.08 mol

ΔH = 41.7 kj

Explanation:

8 0
4 years ago
A student determines the aluminum content of a solution by first precipitating it as aluminum hydroxide, and then decomposing th
Vladimir [108]

Answer: The student should obtain <u>1.103 g of aluminum oxide </u>

Explanation:

  • First we write down the equations that represent the aluminum hydroxide precipitation  from the reaction between the aluminum nitrate and the sodium hydroxide:

Al(NO3)3 + 3NaOH → 3NaNO3 + Al(OH)3

Now,  the equation that represents the decomposition of the hydroxide to aluminum oxide by heating it.

2Al(OH)3 → Al2O3 + 3H2O

  • Second, we gather the information what we are going to use in our calculations.

Volumen of  Al(NO3)3 = 40mL

Molar concentration of Al(NO3)3 =  0.541M

Molecular Weight Al2O3 = 101.96 g/mol

  • Third, we start using the molar concentration of the aluminum nitrate and volume used to find out the total amount of moles that are reacting

\frac{0.541moles Al(NO3)3}{1L} x\frac{1L}{1000mL} x 40mL Al(NO3)3 =  0.022moles Al(NO3)3

then we use the molar coefficients from the  equations to discover the amount of Al2O3  moles produced

0.022moles Al(NO3)3 x \frac{1mol Al(OH)3}{1mol Al(NO3)3} X\frac{1mol Al2O3}{2molAl(OH)3} = 0.011 moles Al2O3

finally, we use the molecular weight of the Al2O3  to calculate the final mass produced.

0.011moles Al2O3 x \frac{101.96g Al2O3}{1mol Al2O3} = 1.103g Al2O3

4 0
4 years ago
Formulas and nomenclature binary ionic compounds worksheet
Leviafan [203]

To name the binary ionic compounds it is necessary to observe which is the metal and the non-metal that compose them.

This name is made as follows:

  1. The name of the metal is shown.
  2. The name of the non-metal is presented in abbreviated form.
  3. Add the suffix "ide" at the end.

An example of this can be seen in the binary ionic composite KCL that receives the name Potassium Chloride, since potassium is the metal and chlorine is the non-metal.

It is important to remember that binary ion compounds are electrically charged ionic molecules formed by a metal and not a non-metal.

You can find more information about ionic bonds at the link below:

brainly.com/question/24500453

5 0
2 years ago
What is the molarity of a solution made of 2.45 moles of LiCl in 4.75 L of solution?
morpeh [17]

Answer:

.52 M

Explanation:

moles ÷ liters = molarity

2.45 ÷ 4.75 = 0.5157894737

rounding it = .52

7 0
3 years ago
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