Answer:

Explanation:
Data:
50/50 ethylene glycol (EG):water
V = 4.70 gal
ρ(EG) = 1.11 g/mL
ρ(water) = 0.988 g/mL
Calculations:
The formula for the boiling point elevation ΔTb is

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.
1. Moles of EG

2. Kilograms of water

3. Molal concentration of EG

4. Increase in boiling point

5. Boiling point
Answer:
d- 334 kJ/g.
Explanation:
You can detect it from the units of the different choices.
a- has the unit J/g.°C that is the unit of the specific heat capacity (c).
b- has the unit Kelvin that is the unit of temperature.
c- has the unit g/mol which is the unit of the molar mass.
d- has the unit kJ/g which is the unit of the enthalpy divided by the no. of rams that is the specific entha;py of fusion.
<em>So, the right choice is: d- 334 kJ/g.</em>
Answer:
think it helps you
<h2>
Explanation:</h2>
<em><u>The statement “the scientific process is open ended” means: Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons? Element 1 is a hard dark-red solid</u></em>
Answer:
Lewis structure for nitrogen triiodide,
is given in the attachment.
Explanation:
Given:
The given compound is Nitrogen triiodide. In which 1 atom of Nitrogen combines with 3 atoms of Iodine. Both Nitrogen and Iodine are non-metals,So they form covalent bond by sharing of electrons.
The electron configuration of Nitrogen and Iodine is given below;

There are 5 electrons in valance shell of Nitrogen atom and 7 electrons in valance shell of Iodine atom.
So, 3 atom of Iodine shares 1 electron with 1 electrons of Nitrogen.
The Lewis dot Structure is in the attachment.
Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.
Explanation:
The statements that are true about 13C NMR are:
A. In 13C proton-decoupled NMR spectra, all peaks are singlets.
C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.
D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry
Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.