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Taya2010 [7]
3 years ago
10

To what volume should 5.06 mL of an 7.83 M sulfuric acid solution be diluted in order to obtain a final solution that is 2.36 M?

Chemistry
1 answer:
Akimi4 [234]3 years ago
4 0

the answer is 16.8 mL H2SO4 (aq).

the formula for dilation is M1*V1=M2*V2, where M is the molarity and V is the volume.

so plugging in...

1. (7.83)(5.06)=2.36*V2

2. multiply 7.83 and 5.06 then divide that by 2.36

3. V2= 16.788050...

4. to three sigfigs (because the problem has a minimum of 3) is 16.8 mL H2SO4 (aq).

i hope this is correct! i did it without pencil and paper and i’m currently learning this too! if it’s wrong i’m so truly sorry :(

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Answer:

650 grams

Explanation:

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8 0
3 years ago
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Answer:

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Explanation:

Given data:

Mass of Zn = 5 g

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Mass of zinc chloride produced = ?

Solution:

Chemical equation:

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Number of moles of Zn:

Number of moles = mass / molar mass

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Number of moles = mass / molar mass

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Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

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The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

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Mass = 11 g

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