To what volume should 5.06 mL of an 7.83 M sulfuric acid solution be diluted in order to obtain a final solution that is 2.36 M?
1 answer:
the answer is 16.8 mL H2SO4 (aq).
the formula for dilation is M1*V1=M2*V2, where M is the molarity and V is the volume.
so plugging in...
1. (7.83)(5.06)=2.36*V2
2. multiply 7.83 and 5.06 then divide that by 2.36
3. V2= 16.788050...
4. to three sigfigs (because the problem has a minimum of 3) is 16.8 mL H2SO4 (aq).
i hope this is correct! i did it without pencil and paper and i’m currently learning this too! if it’s wrong i’m so truly sorry :(
You might be interested in
Answer:
1600
Explanation:
5×10^4÷2.5×10^2
(5×10^4)
(10^4)
(5×40)
(200)
(200÷2.5)
(80)
(80×10^2)
(10^2)
(20)
(80×20)
Answer is 1600.
Sorry if it's not correct.
Answer:
Group 1
Explanation: because the compound has a formula of M2O , the number of valence electrons of M should be 1.
Answer:
The chemical elements are arranged in order of increasing atomic number.
Explanation:
Hydrogen = 1
Helium = 2
Lithium = 3
It would be potassium chloride or kcl
Answer:
(NH4)2Cr2O7
Explanation:
Hope this somehow helped.
