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s344n2d4d5 [400]
3 years ago
13

What is the rule of electric charges? A. Opposite charges attract; like charges repel. B. How charges react is unpredictable. C.

Like charges attract; unlike charges push away. D. Charges that are the same will pull toward each other.
Physics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

The answer is A. Opposite charges attract; like charges repel.

hope this helps, pls mark me Brainliest

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Which lines are parallel to the graph of 4x – y = 6? Check all that apply.
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The parallel lines have same slope.

we find the slope from slope intercept form for the given line: <span>4x – y = 6
y = 4x - 6
here slope is m = 4

Now, The equations which are parallel to the given line are:

1) </span><span>y + 1 = 4(x – 2) or y = 4x - 7 , here m = 4
2)</span><span>y = 4x + 11 , here m = 4
3) </span><span>8x – 2y = 6, here , m= 4</span>
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Which of the following best describes longitudinal waves
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sergejj [24]

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A block is attached to a spring hanging vertically. After being slowly lowered, it hangs at rest with the spring stretched by 15
artcher [175]

Answer:

The equilibrium position is 15 cm below the starting point. The motion is symmetric about the equilibrium position, so the two turning points are 30 cm apart.

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3 years ago
A solid sphere rolls along a horizontal, smooth surface at a constant linear speed without slipping. What is the ratio between t
dsp73

Answer:

option E

Explanation:

given,

Rotational Kinetic Energy, KE_r = \dfrac{1}{2}I\omega^2

Moment of inertia of the solid,

I = \dfrac{2}{5}MR^2

\omega = \dfrac{V}{R}

now,

KE_r = \dfrac{1}{2}I\omega^2

KE_r = \dfrac{1}{2}\times \dfrac{2}{5}MR^2 (\dfrac{V}{R})^2

KE_r =\dfrac{1}{5}MV^2......(1)

transnational kinetic energy

KE_t =\dfrac{1}{2}MV^2

Total kinetic energy

KE = \dfrac{1}{2}MV^2 + \dfrac{1}{5} MV^2

KE = \dfrac{7}{10}MV^2

ratio of rotational kinetic energy to the total kinetic energy

\dfrac{KE_r}{KE_t}=\dfrac{\dfrac{1}{5}MV^2}{\dfrac{7}{10}MV^2}

\dfrac{KE_r}{KE_t}=\dfrac{2}{7}

hence, the correct answer is option E

4 0
3 years ago
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