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KiRa [710]
3 years ago
5

A cylindrical specimen of this alloy 12.7 mm in diameter and 250 mm long is stressed in tension and found to elongate 7.6 mm. On

the basis of the information given, is it possible to compute the magnitude of the load that is necessary to produce this change in length? If so, calculate the load. If not, explain why.
Engineering
1 answer:
Margarita [4]3 years ago
5 0

Answer:

Condition 2 is true.

\epsilon_{test}>\epsilon_{yield}

we can not calculate the load with given information.

According to above values, Condition 2 is satisfied so we can not find the load with given information because material deformation lies in plastic region.

Explanation:

In order to check whether we can find the load or not we have to check the following conditions:

Condition 1:

\epsilon_{test}

If this condition is true then we can calculate the load.

Condition 2:

\epsilon_{test}>\epsilon_{yield}

If this condition is true then we can not calculate the load with given information.

Calculating \epsilon_{test}:

\epsilon_{test}=\frac{Elongation}{original\ length}

\epsilon_{test}=\frac{7.6\ mm}{250\ mm}\\ \epsilon_{test}=0.0304

Calculating \epsilon_{yield}:

\epsilon_{yield}=\frac{Yield\ Stress}{Elastic\ modulus}\\ \epsilon_{yield}=\frac{280\ Mpa}{105*10^3\ MPa} \\\epsilon_{yield}=2.67*10^{-3}=0.00267

Hence:

Condition 2 is true.

\epsilon_{test}>\epsilon_{yield}

According to above values, Condition 2 is satisfied so we can not find the load with given information because material deformation lies in plastic region.

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Yes

Explanation:

Given Data

Temprature of source=750°c=1023k

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Work produced=3.3KW

Heat Rejected=4.4KW

Efficiency of heat engine(η)=\frac{Work produced}{Heat supplied}

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{Q_s}=3.3+4.4=7.7KW

η=\frac{3.3}{7.7}

η=42.85%

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η=1-\frac{273}{1023}

η=73.31%

Therefore our Engine Efficiency is less than the maximum efficiency hence the given claim is valid.

5 0
3 years ago
In a manufacturing facility, 2-in-diameter brass balls (k = 64.1 Btu/h·ft·°F, rho = 532 lbm/ft^3, and cp = 0.092 Btu/lbm·°F) ini
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Explanation:

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4 0
4 years ago
Read 2 more answers
Write a function call with arguments tensPlace, onesPlace, and userInt. Be sure to pass the first two arguments as pointers. Sam
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Answer:

#include <stdio.h>

void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){

  *tensDigit = (DecVal / 10) % 10;

  *onesDigit = DecVal % 10;

  return;

}

int main(void) {

  int tensPlace = 0;

  int onesPlace = 0;

  int userInt = 0;

  userInt = 41;

  SplitIntoTensOnes(&tensPlace, &onesPlace, userInt);

  printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace);

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4 0
3 years ago
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Answer:

21.456 kJ/h

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See the figure attached. In this case  

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Q_{out} = 21.456 \frac{kJ}{h}

3 0
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