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KiRa [710]
3 years ago
5

A cylindrical specimen of this alloy 12.7 mm in diameter and 250 mm long is stressed in tension and found to elongate 7.6 mm. On

the basis of the information given, is it possible to compute the magnitude of the load that is necessary to produce this change in length? If so, calculate the load. If not, explain why.
Engineering
1 answer:
Margarita [4]3 years ago
5 0

Answer:

Condition 2 is true.

\epsilon_{test}>\epsilon_{yield}

we can not calculate the load with given information.

According to above values, Condition 2 is satisfied so we can not find the load with given information because material deformation lies in plastic region.

Explanation:

In order to check whether we can find the load or not we have to check the following conditions:

Condition 1:

\epsilon_{test}

If this condition is true then we can calculate the load.

Condition 2:

\epsilon_{test}>\epsilon_{yield}

If this condition is true then we can not calculate the load with given information.

Calculating \epsilon_{test}:

\epsilon_{test}=\frac{Elongation}{original\ length}

\epsilon_{test}=\frac{7.6\ mm}{250\ mm}\\ \epsilon_{test}=0.0304

Calculating \epsilon_{yield}:

\epsilon_{yield}=\frac{Yield\ Stress}{Elastic\ modulus}\\ \epsilon_{yield}=\frac{280\ Mpa}{105*10^3\ MPa} \\\epsilon_{yield}=2.67*10^{-3}=0.00267

Hence:

Condition 2 is true.

\epsilon_{test}>\epsilon_{yield}

According to above values, Condition 2 is satisfied so we can not find the load with given information because material deformation lies in plastic region.

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Answer:

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Explanation:

From definition of engineering stress, \sigma=\frac {F}{A}

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Also, engineering strain, \epsilon=\frac {\triangle l}{l} where l is original area and \triangle l is elongation

We also know that Hooke's law states that E=\frac {\sigma}{\epsilon}=\frac {\frac {F}{A}}{\frac {\triangle l}{l}}=\frac {Fl}{A\triangle l}

Since A=20 mm* 20 mm= 0.02 m*0.02 m

F= 89000 N

l= 100 mm= 0.1 m

\triangle l= 0.1 mm= 0.1\times 10^{-3} m

By substitution we obtain

E=\frac {89000\times 0.1}{0.02^{2}\times 0.1\times 10^{-3}}=2.225\times 10^{11}= 225.5 Gpa

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Explanation:

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For some metal alloy, the following engineering stresses produce the corresponding engineering plastic strains prior to necking.
kirza4 [7]

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2 years ago
Say you have a random, unordered list containing 4096 four-digit numbers. Describe the most efficient way to: sort the list and
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Answer:

Answer explained below

Explanation:

It is given that numbers are four-digit so maximum value of a number in this list could be 9999.

So we need to sort a list of integers, where each integer lies between [0,9999].

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--------------------------------------------------------------------------------

Psuedo Code:

countSort(int numList[]) {

int count[10000];

count[i] = 0; for all i;

for(int num in numList){

count[num]+= 1;

}

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}

--------------------------------------------------------------------------------

Searching in this count array will be just O(1).

E.g. Lets say we want to search if 3 was present in the original list.

Case 1: it was present in the original list:

Then the count[3] would have been incremented by our sorting algorithm. so in case element exists then count value of that element will be greater than 0.

Case 2: it was not present:

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