Answer:
Acceleration, ![a=\dfrac{1}{8}(-i+9j)\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B1%7D%7B8%7D%28-i%2B9j%29%5C%20m%2Fs%5E2)
Explanation:
Initial velocity of a particle in vector form, u = (-5i - 2j) m/s
Final velocity of particle in vector form, v = (-6i + 7j) m/s
Time taken, t = 8 seconds
We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :
![a=\dfrac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D)
or
![a=\dfrac{1}{8}(-i+9j)\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B1%7D%7B8%7D%28-i%2B9j%29%5C%20m%2Fs%5E2)
Hence, the value of acceleration vector is solved.
Answer:
B.Focused,warm
Explanation:
when the rays are focused more energy an area recieves and it is warmer there.
Aristotle believed that the Earth was orbited by the sun, moon, and the other planets which he referred to as Celestial Bodys
Answer:
Speed is greater in trial 2
Explanation:
"<em>Indicate whether the speed of the block relative to the table when the block reaches the bottom of the plane is greater in trial 1 or trial 2.</em>"
The initial potential energy of the block is converted into kinetic energy, with no work done by friction.
In Trial 1, the ramp is free to move, so both the block and the ramp have kinetic energy.
PE = KE + KE
mgh = ½ mv₁² + ½ Mv²
In Trial 2, the ramp is fixed, so only the block has kinetic energy.
PE = KE
mgh = ½ mv₂²
Setting the expressions equal:
½ mv₁² + ½ Mv² = ½ mv₂²
Therefore, v₂ must be greater than v₁.