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MAXImum [283]
3 years ago
9

In an experiment, 26.5 g of metal was heated to 98.0°c and then quickly transferred to 150.0 g of water in a calorimeter. the in

itial temperature of the water was 20.0°c, and the final temperature after the addition of the metal was 32.5°c. assume the calorimeter behaves ideally and does not absorb or release heat.
Chemistry
1 answer:
allsm [11]3 years ago
4 0
This is a common laboratory experiment called calorimetry which determines the specific heat capacity of the sample metal. 

By the Conservation of Energy,

Energy of Metal = Energy of Water
mCmetalΔT = mCwaterΔT, wherein Cwater = 4.187 J/g·°C
(26.5 g)(Cmetal)(98 - 32.5°C) = (150 g)(4.187 J/g·°C)(32.5 - 20°C)
Solving for Cmetal,
<em>Cmetal = 4.523 J/g·°C</em>
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