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Mazyrski [523]
3 years ago
7

When 224-nm light falls on a metal, the current through a photoelectric circuit is brought to zero at a stopping voltage of 1.84

V. What is the work function of the metal?
Physics
1 answer:
OLga [1]3 years ago
7 0

Answer:

3.71 eV

Explanation:

λ = Wavelength of light = 224 nm = 224 x 10⁻⁹ m

c = speed of electromagnetic wave = 3 x 10⁸ m/s

V₀ = stopping potential = 1.84 volts

W₀ = Work function of the metal = ?

Using the equation

\frac{hc}{\lambda } = eV_{o} + W_{o}

\frac{(6.63\times 10^{-34})(3\times 10^{8})}{224\times 10^{-9} } = (1.6\times 10^{-19})(1.84) + W_{o}

W_{o} = 5.94 x 10⁻¹⁹

W_{o} = 3.71 eV

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