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mel-nik [20]
3 years ago
15

Pls help quick too.................

Physics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

Pulley = Flag Pole

Screw = Side latch

Wedge = Scissors

Wheel and axle = Car

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What features did you find most interesting about the Elizabethan-era globe theatre? Check any that apply
sweet [91]

Answer: 1,2,3,4,6 are all correct

Explanation:

i just took the test and got them all right

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3 years ago
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A bullet is fired from a rifle pointed 45 degrees above horizontal. The bullet leaves the muzzle traveling 1400 m/s. How many se
Bogdan [553]

The bullet's vertical velocity at time t is

v=1400\dfrac{\rm m}{\rm s}-gt

where g=9.80\frac{\rm m}{\mathrm s^2} is the acceleration due to gravity.

At its highest point, the bullet's vertical velocity is 0, which happens

0=1400\dfrac{\rm m}{\rm s}-gt\implies t=\dfrac{1400\frac{\rm m}{\rm s}}g\approx\boxed{142.857\,\mathrm s}

(or about 140 s, if you're keeping track of significant figures) after being fired.

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3 years ago
What is impossible for a machine to do
oee [108]

Answer:

Create a living person.

Explanation:

4 0
4 years ago
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A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to en
Nina [5.8K]

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

  • dl'=3.621*10^{-4}m

From the question we are told

A copper (<em>Young's modulus </em>1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each <em>cylinder </em>has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack <em>decreases</em>.

Generally the equation for <em>copper </em>cylinder   is mathematically given as

dl=\frac{Flo}{yA}

dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}

dl=1.19064778*10^-^4

Generally the equation for brass<em> </em>cylinder   is mathematically given as

dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}

dl=2.43*10^{-4}

Therefore Total change in length

dl'=1.191*10^-^4+(2.43*10^{-4})

dl'=3.621*10^{-4}m

For more information on this visit

brainly.com/question/23379286

3 0
3 years ago
Daisy walks across a force platform, and forces exerted by her foot during a step are recorded. The peak velocity reaction force
Len [333]

Answer:

(a). The resultant of these forces is 1216.55 N.

(b).  The direction of the resultant forces is 80.53°.

Explanation:

Given that,

First force = 1200 N

Second force = 200 N

(a). We need to calculate the resultant of these forces

Using cosine law

F=\sqrt{F_{1}^2+F_{2}^2+2F_{1}F_{2}\cos\theta}

Put the value into the formula

F=\sqrt{1200^2+200^2+2\times1200\times200\cos90}

F=\sqrt{1200^2+200^2}

F= 1216.55\ N

The resultant of these forces is 1216.55 N.

(b). We need to calculate the direction of the resultant forces

Using formula of direction

\tan\alpha=\dfrac{F_{1}}{F_{2}}

Put the value into the formula

\alpha=\tan^{-1}(\dfrac{1200}{200})

\alpha=80.53^{\circ}

Hence, (a). The resultant of these forces is 1216.55 N.

(b).  The direction of the resultant forces is 80.53°.

4 0
3 years ago
Read 2 more answers
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