Plutonium-239 undergoes alpha decay and has a half-life of 24, 000 years . After 72, 000 years, how much of an initial 100.0 sam ple will remain?
1 answer:
Hey there!
A half-life means after a certain amount of time, half of that substance will have decayed after that time.
There are 3 half-lives in 72,000 years because 72,000 ÷ 24,000 = 3.
So, we divide the 100g sample in half 3 times.
100 ÷ 2 = 50
50 ÷ 2 = 25
25 ÷ 2 = 12.5
There will be 12.5g of the radioactive sample remaining after 72,000 years.
Hope this helps!
You might be interested in
The formula for lead (ii) chromate is: PbCrO4
Answer:
T final = 80°C
Explanation:
∴ Q = 18000 cal
∴ m H2O = 300 g
∴ Cp H2O (15°C) = 0.99795 cal/g.K ≅ 1 cal/g.K
∴ T1 = 20°C = 293 K
∴ T2 = ?
⇒ 18000 cal = (300 g)(1 cal/g.K)(T2 - 293 K)
⇒ (18000 cal)/(300 cal/K) = T2 - 293 K
⇒ T2 = 293 K + 60 K
⇒ T2 = 353 K (80°C)
It’s B because of the quest
Please show the whole question including the diagram so that you can receive help with the question.
Answer: Redox Reaction
Explanation:
Redox reaction is the key chemical events in an oxidation-reduction also called Redox. It is the net movement of electrons from one reactants to another
