Answer:
Has a hydroxide concentration of 0.01M
Explanation:
When NaOH dissociates, it gives 1mol Na+ and 1mol OH- this multiplies the concentration value and we get 0.01×1= 0.01M
The volume of H₃PO₄ : 13.33 ml
<h3>Further explanation</h3>
Given
0.003 M Phosphoric acid-H₃PO₄
40 ml of 0.00150 M Calcium hydroxide-Ca(OH)₂
Required
Volume of H₃PO₄
Solution
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence (amount of H⁺/OH⁻)
H₃PO₄⇒3H⁺ + PO₄³⁻ ⇒ 3 H⁺ = valence = 3
Ca(OH)₂⇒Ca²⁺ + 2OH⁻⇒ 2 OH⁻ = valence = 2
Input the value :
a = H₃PO₄, b = Ca(OH)₂
0.003 x Va x 3 = 0.0015 x 40 x 2
Va = 13.33 ml
MH₂: 2 g/mol
mNH₃: 17 g/mol
...............................
3H₂ + N₂ ---> 2NH₃
6g......................34g
6g H₂ ---- 34g NH₃
Xg -------- 13,09g
X = (6×13,09)/34
X = 2,31g H₂
Answer: O fluorine to complete the octet rule
that right
