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balandron [24]
3 years ago
15

Which of the following is not a correct chemical equation for a double displacement reaction? (2 points) 2RbNO3 + BeF2yields Be(

NO3)2 + 2RbF CaCl + LiCO3yields CaCO3 + LiCl Na3PO4 + 3KOH yields 3NaOH + K3PO4 2MgI2 + Mn(SO3)2yields 2MgSO3 + MnI4
Chemistry
1 answer:
UNO [17]3 years ago
6 0

Answer: 2MgI_2+Mn(SO_3)_2\rightarrow 2MgSO_3+MnI_4

Explanation:

Double displacement reaction: it is a chemical reaction in which the reactants  exchanges their ions to form new compounds as a products.

AB+CD\rightarrow AD+CB

All the reaction are example of double displacement reaction beside reaction where magnesium iodide is reacting with manganese(II) sulfate to give magnesium sulfate and manganese(IV) iodide .

2MgI_2+Mn(SO_3)_2\rightarrow 2MgSO_3+MnI_4

In this reaction , charge on manganese have changed from 2+ to 4+.  Manganese in getting oxidized. Example of an oxidation reaction. Hence, this reaction is not an example of double displacement reaction.

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At 40°C, how much KNO3 is<br> soluble?
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4 years ago
Calculate the number of mg of Mn2+ left
soldi70 [24.7K]

Answer:

1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.

Explanation:

The reaction that takes place is:

Mn⁺² + S⁻² ⇄ MnS(s)  

ksp = [Mn⁺²] [S⁻²]

If the pksp of MnS is 13.500, then the ksp is:

ksp=10^{-13.500}=3.1623*10^{-14}

From the problem we know that [S⁻²] = 0.0900 M

We use the ksp to calculate [Mn⁺²]:

3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M

[Mn⁺²] = 3.514 * 10⁻¹³ M.

Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:

3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.

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3 years ago
What is the mass of 4.25 liters of N2 gas at STP?
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We know that 1 mole of anything has a volume of 22.4 liters.

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I think the correct answer is traits. Please brainiest me! :)
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