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AnnZ [28]
3 years ago
13

Study the diagram below to the following question.which of the above images is a molecule?

Chemistry
1 answer:
kotegsom [21]3 years ago
4 0
I can help you I just need the image

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If the patient has to be administered a dosage of 2 tablets every 8 hours for 7 days, what is the number of tablets required for
Lilit [14]
If the patient has to take 2 tablets every 8 hours for 7 days.
 24/8=3     3*2=6
this means that he patient will have to take 6 tablets every day. 
6*7=42   And the patient must take 42 tablets in all 7 days
Hope this helps! :)
6 0
3 years ago
How does weathering change rock and minerals
Phantasy [73]

Weathering is the process of breaking large rocks and boulders into much smaller ones. Weathering can be brought about by wind and water mostly. Sometimes even biological forces account for some types of weathering.

3 0
3 years ago
Read 2 more answers
What mass of bromine reacts with 16.2 g of aluminium?
Goshia [24]
For every, 3 Br- ions, 1 Al3+ ion reacts to form AlBr3.

Convert 16.2g of aluminum to moles:

16.2g Al / 27.0g per mol = 0.60 mols.

Based on the above ratio, 0.60 mols of Al will react with 1.8 mols of Br.

Convert 1.8 mols of Br to its mass:

1.8 mols Br × 79.9g per mol = 143.82g of Br.
6 0
3 years ago
You now know that [Pb+2] = 0.17 M. Calculate [Cl-].
iris [78.8K]

Answer:

0.34 M

Explanation:

I assume that the compound is PbCl2.

One mole of PbCl2 contains one mol of Pb+2 and 2 moles of Cl-

Molarity (M)= moles (n) /Volume (V)

Moles Pb2+ = M x V = 0.17 V

Moles Cl- = moles Pb2+ x (2 moles Cl-/1 mole Pb2+) = 0.17 V x 2 = 0.34 V

M Cl- = moles Cl-/V = 0.34V/V = 0.34 M

6 0
2 years ago
Balance the following redox equation, using half-reactions. Assume that the reaction occurs in an aqueous solution.
anastassius [24]
First determine the formal oxidation numbers: 
N changes from +2 to +5 going from NO to (NO3)- O remains -2 the whole time Cr changes from +6 to +3 
Now write the half reactions, balance the oxygens with the required number of waters and then balance the hydrogens with the required number of protons: 
Oxidation half reaction: 
NO(aq) + 2 H2O(l) ---> (NO3)-(aq) + 4 H+(aq) + 3 e- 
Reduction half reaction: 
(Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l) 
Now balance the number of electrons on both sides and add them together: 
2 NO(aq) + 4 H2O(l) ---> 2 (NO3)-(aq) + 8 H+(aq) + 6 e- (Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l) --------------------------------------... 2 NO(aq) + (Cr2O7)2-(aq) + 6 H+(aq) ---> 2 (NO3)-(aq) + 2 Cr3+(aq) + 3 H2O(l) 
Notice that the charge is the same in both sides, which is an indication that the redox equation has been balanced correctly: 
-2 + 6 = -2 + 2(+3) +4 = +4 
5 0
3 years ago
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