Answer:
distance between the dime and the mirror, u = 0.30 m
Given:
Radius of curvature, r = 0.40 m
magnification, m = - 2 (since,inverted image)
Solution:
Focal length is half the radius of curvature, f = 
f = 
Now,
m = - 
- 2 = -
= 2 (2)
Now, by lens maker formula:


v =
(3)
From eqn (2):
v = 2u
put v = 2u in eqn (3):
2u = 
2 = 
2(u - 0.20) = 0.20
u = 0.30 m
Answer:
The breaking in <em>molecular</em> bonds in food releases energy for your body to use.
A would be the wavelength, C would be a crest, D would be the amplitude, leaving B which is the trough.
Answer:
2625 m deep
Explanation:
Let the sound speed in sea water be 1500 m/s. If he hears the echo 3.5s after the strike, then the sound would have traveled a distance of 1500 * 3.5 = 5250 m to the bottom and back. This would mean the ocean is 5250 / 2 = 2625 m deep.
Answer:
2 x 10^20 N
Explanation:
Me = 5.98 x 10^24 kg
Mm = 7.36 x 10^22 kg
r = 3.82 x 10^5 km = 3.82 x 10^8 m
The gravitational force between earth and moon is
F = G Me x Mm / r^2
F = (6.67 x 10^-11 x 5.98 x 10^24 x 7.36 x 10^22) / (3.82 x 10^8 x 3.82 x 10^8)
F = 2 x 10^20 N