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pshichka [43]
3 years ago
10

An average human has a heart rate of 70 beats per minute. If someone's heart

Physics
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

I believe it would be D).3 x 10 to the 9th power

Explanation:

MariettaO [177]3 years ago
3 0
3x10 to the 9th power, the answer is D
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Can you make the work output of a machine greater than the work input?
ExtremeBDS [4]

Answer:

It is<em> impossible</em> to construct a machine which produces the <em>work output greater than the work input.</em>

Let us consider the II law of thermodynamics.

According to Kelvin Plank's statement any engine/machine does not give hundred percent efficiency. And violating the PMM-II(Perpetual motion of machine II kind), Always some amount of energy transferred  to the sink or surroundings.

Therefore

                     W(ouput) = Q₁-Q₂

There are many reasons to lower the work output, just for an example friction between the mating parts reduces the work output.

5 0
3 years ago
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in physics lab, a cube slides down a frictionless incline as shown in the figure below, and elastically strikes another cube at
Tema [17]
<span>In the physics lab, a cube slides down a frictionless incline as shown in the figure below, check the image for the complete solution:

</span>

3 0
3 years ago
Which is a characteristic of the part of the atom marked "A"?Which is a characteristic of the part of the atom marked "A"?Which
WITCHER [35]

Here's link to the answer:

tinyurl.com/wpazsebu

4 0
2 years ago
Read 2 more answers
PLEASE HELP
blagie [28]
Assuming Adam is on earth g= 9.8 m/s and m= weight/ gravity = 667/9.8 = 68 kg
8 0
3 years ago
Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the
MA_775_DIABLO [31]

Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

Then you have:

Mv_{1o}+mv_{2o}=(M+m)v        (1)

M: mass Betty = 40kg

m: mass of the dog = 15kg

v1o: initial speed of Betty = 3.0m/s

v2o: initial speed of the dog = 0 m/s

v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

v=\frac{Mv_{1o}+mv_{2o}}{M+m}=\frac{(40kg)(3.0m/s)+(15kg)(0m/s)}{40kg+15kg}\\\\v=2.18m/s

The speed fo both Betty and her dog is 2.18m/s

7 0
2 years ago
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