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pshichka [43]
3 years ago
10

An average human has a heart rate of 70 beats per minute. If someone's heart

Physics
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

I believe it would be D).3 x 10 to the 9th power

Explanation:

MariettaO [177]3 years ago
3 0
3x10 to the 9th power, the answer is D
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A spring stretches 1.68cm vertically when a 2.50kg object is suspended from it.Find the distance (in cm) the spring stretches if
Llana [10]

Answer:

2.96 cm

Explanation:

By Hook's law

Force(F) = Spring constant(k) × Extension(d)

 F = k × d

Force is the weight of the object, F = W = mg

So we get, mg = kd ⇒ m ∝ d

                                   2.5 ∝ 1.68  --------------(1)

                                   4.4 ∝ d'      --------------(2)

From (1) & (2),     4.4/2.5 = d'/1.68

                                   d' = 2.96 cm ⇒ the required extension.

7 0
3 years ago
A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren
ludmilkaskok [199]

Answer : Height, h = 20.4 m

Explanation :

It is given that,

Mass of an object, m = 500 g = 0.5 kg

Gravitational potential energy, PE = 100 J

The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :

PE = m g h

where,

h is the height of the cliff.

100\ J=0.5\ kg\times 9.8\ m/s^2\times h

h = 20.40 m

So, the height of the cliff is 20.4 m.

7 0
3 years ago
If I toot 88 times what did that mean
Degger [83]

Answer:Nazi skinhead code for Heil Hitler. H being the 8th letter of the alphabet, therefore HH=88.

Explanation:

8 0
3 years ago
High altitude high velocity rivers of air are called
forsale [732]
The answer to the question would be jet streams.
3 0
3 years ago
Read 2 more answers
Assuming that the uncertainty in mass is negligible, and the uncertainty in velocity is 5 %, what is the uncertainty in the mome
Flura [38]

Answer:

 Δp = 0.05 p

Explanation:

The moment is

      p = m v

The uncertainty of the moment is

       Δp = dp/dm Δm + dp/dv Δv

Like the uncertainty in the mass is zero

       Δm = 0

       ΔP = m Δv

We divide for the moment

       Δp / p = Δv / v

  They do not indicate that Δv / v = 0.05

       Δp / p = 0.05

       Δp = 0.05 p

In the case of a system consisting of two cars

      p = m₁ v₁ + m₂ v₂

     Δp = dp / dv₁ Δv₁ + dp / dv₂ Δv₂

     Δp = m₁ Δv₁ + m₂ Δv₂

     Δv₁ / v₁ = 0.05

     Δv₁ = 0.05 v₁

     Δv₂ / v₂ = 0.05

     Δv₂ = 0.05 v₂

We replace

       Δp = m₁ 0.05 v₁ + m₂ 0.05 v₂

       Δp = 0.05 p

8 0
3 years ago
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