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2 answers:
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Answer:
0.087 m
Explanation:
Length of the rod, L = 1.5 m
Let the mass of the rod is m and d is the distance between the pivot point and the centre of mass.
time period, T = 3 s
the formula for the time period of the pendulum is given by
.... (1)
where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.
Moment of inertia of the rod about the centre of mass, Ic = mL²/12
By using the parallel axis theorem, the moment of inertia of the rod about the pivot is
I = Ic + md²
Substituting the values in equation (1)
12d² -26.84 d + 2.25 = 0
d = 2.15 m , 0.087 m
d cannot be more than L/2, so the value of d is 0.087 m.
Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.
The force per unit length between the two wires is
Explanation:
The magnitude of the force per unit length exerted between two current-carrying wires is given by
where
is the vacuum permeability
are the currents in the two wires
r is the separation between the two wires
For the wires in this problem, we have
r = 2.00 cm = 0.02 m
Substituting into the equation, we find
Learn more about current and magnetic fields:
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