Setting StartFraction 7 over 3 EndFraction equal to which ratio would result in a valid proportion?

Mathematics

2 answers:

pochemuha3 years ago

6 0

Answer:

Option C is correct

Step-by-step explanation:

In this question, we are asked to select which of the options have the same value as 7/3

We examine the options one urge other.

Option A

9/49; This is wrong as it cannot be divided further to yield while multiples

Option B

18/42; Dividing through by 6 will yield 3/7 which is not same as 7/3; This makes this option wrong too

Option C

42/18; dividing through by 6 will yield 7/3 which makes this option correct

Option D

49/9; This is a dead end as it cannot be divided further to give whole number multiples

sveticcg [70]3 years ago

3 0

Answer:

C the answer is 18/4

Step-by-step explanation:

You might be interested in

HELP!!!!!!!!!!!!!!!!!

Nezavi [6.7K]

A. 5^3 * 5^4 = 78,125

4 0

3 years ago

An 18-foot ladder leaned up against a wall forms an angle of 70 degrees with the ground. How high up the wall will the ladder re

Paladinen [302]

the ladder is 13.8 ft up the wall

6 0

3 years ago

Write an expression that represents sarah's total pay last week. represent her hourly wage with

Nostrana [21]

Whats her hourly wage and where is the rest of the question this is very confusing there are no details so i cannot help you sorry

5 0

3 years ago

Help for question 7 please

scoray [572]

◆ COMPLEX NUMBERS ◆

$given \: expression \: is \: - \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{ - 9} \\ \\ we \: know \: that \: , \: \\ i = \sqrt{ - 1} \\ \\ {i}^{2} = - 1 \\ \\ {i}^{3 } = - i \\ \\ {i}^{4} = 1 \\ \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{9} i \\ = - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + 3i \\ \\ using \: the \: above \: properties \: of \: iota \: (i) \\ \\ = - 3(1) + 2( - i) + 2( - 1) + 3i \\ \\ = - 3 - 2i - 2 + 3i \\ \\ = (- 5 + i) \: \: \: ans.$