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Aleks04 [339]
3 years ago
13

Setting StartFraction 7 over 3 EndFraction equal to which ratio would result in a valid proportion?

Mathematics
2 answers:
pochemuha3 years ago
6 0

Answer:

Option C is correct

Step-by-step explanation:

In this question, we are asked to select which of the options have the same value as 7/3

We examine the options one urge other.

Option A

9/49; This is wrong as it cannot be divided further to yield while multiples

Option B

18/42; Dividing through by 6 will yield 3/7 which is not same as 7/3; This makes this option wrong too

Option C

42/18; dividing through by 6 will yield 7/3 which makes this option correct

Option D

49/9; This is a dead end as it cannot be divided further to give whole number multiples

sveticcg [70]3 years ago
3 0

Answer:

C the answer is 18/4

Step-by-step explanation:

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Answer:

hope this helps you

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3 years ago
Which point is a solution to the linear inequality y < x 2? (2, 3) (2, 1) (3, –2) (–1, 3)
gayaneshka [121]

Alternative 1

we have

y < x+2

we know that

If a point is a solution of the inequality

then

the point must be satisfy the inequality

we're going to verify all the points.

<u>case A)</u> point (2,3)

Substitute the value of x and the value of y in the inequality

x=2\ y=3

y < x+2

3 < 2+2

3 < 4 ------> is true

therefore

The point (2,3) is a solution of the inequality

<u>case B)</u> point (2,1)

Substitute the value of x and the value of y in the inequality

x=2\ y=1

y < x+2

1< 2+2

1 < 4 ------> is true

therefore

The point (2,1) is a solution of the inequality

<u>case C)</u> point (3,-2)

Substitute the value of x and the value of y in the inequality

x=3\ y=-2

y < x+2

-2< 3+2

-2 < 5 ------> is true

therefore

The point (3,-2) is a solution of the inequality

<u>case D)</u> point (-1,3)

Substitute the value of x and the value of y in the inequality

x=3\ y=-2

y < x+2

3< -1+2

3 < 1 ------> is not true

therefore

The point(-1,3) is not a solution of the inequality

Alternative 2

we have

y < x-2

we know that

If a point is a solution of the inequality

then

the point must be satisfy the inequality

we're going to verify all the points.

<u>case A)</u> point (2,3)

Substitute the value of x and the value of y in the inequality

x=2\ y=3

y < x-2

3 < 2-2

3 < 0 ------> is not true

therefore

The point (2,3) is not a solution of the inequality

<u>case B)</u> point (2,1)

Substitute the value of x and the value of y in the inequality

x=2\ y=1

y < x-2

1< 2-2

1 < 0 ------> is not true

therefore

The point (2,1) is not a solution of the inequality

<u>case C)</u> point (3,-2)

Substitute the value of x and the value of y in the inequality

x=3\ y=-2

y < x-2

-2< 3-2

-2 < 1 ------> is true

therefore

The point (3,-2) is a solution of the inequality

<u>case D)</u> point (-1,3)

Substitute the value of x and the value of y in the inequality

x=3\ y=-2

y < x-2

3< -1-2

3 < -3 ------> is not true

therefore

The point (-1,3) is not a solution of the inequality


4 0
3 years ago
Read 2 more answers
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krok68 [10]

Answer:

23+26+17=66

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Step-by-step explanation:

as written in the question add (23+26+17)

then divide it with 7 and you'll get 9.42... i think!!

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What’s is the sum of the series?
STALIN [3.7K]

Answer:

<h2>44</h2>

Step-by-step explanation:

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3 years ago
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