Answer:
ΔL = 1.68 mm
σ = 84 MPa
Explanation:
Thermal expansion is:
ΔL = α ΔT L
Thermal stress is:
σ = α ΔT E
Given:
α = 1.2×10⁻⁵ /°C
E = 1.0×10⁵ MPa
ΔT = 80°C − 10°C = 70°C
L = 2 m
ΔL = (1.2×10⁻⁵ /°C) (70°C) (2 m)
ΔL = 0.00168 m
ΔL = 1.68 mm
σ = (1.2×10⁻⁵ /°C) (70°C) (1.0×10⁵ MPa)
σ = 84 MPa
Answer:
33.4
Explanation:
Step 1:
\sumMo=0 (moment about the origin)
Fb(15)-Fc(15)=0
Fb=Fc
Step 2:
\sumFx=0
-Fb-Fccos\theta+Ncsin\theta=0
Fc=0.3Nc=Fb
-0.3Nc-0.3Nccos\theta+Ncsin\theta=0
(-0.3-cos\theta+sin\theta)Nc=0----(1)
\sumFy=0
Nccos\theta+Fcsin\theta-Nb=0
Nccos\theta+0.3Ncsin\theta-Nc=0
Nc[cos\theta+0.3sin\theta-1]=0--------(2)
Solving eq (1) and eq (2)
\theta=33.4
Step 3:
As the roller is a two force member
2(90-\phi)+\theta=180
\phi=\theta/2
\phi=Tan(\muN/N)-1
\phi=16.7
\theta=2x16.7=33.4
Economic cost is a rescission making tangible factor true
Answer:
One inlet stream to the mixer flows at 100.0 kg/hr and is 35wt% species-A and 65wt% species-B.
Explanation:
