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3 years ago

Why are energy pyramids usually no more than 4 trophic levels?

1 answer:

4 0

There are usually no more than four trophic levels, because of the huge loss of energy at each trophic levels. Alomost 10 percent of the energy is lost at each level, as compared to the previous level, which occurs due to wastage of materials like bones and leftover tissues. So, till the fourth trophic level, very less energy is left to be continued to another level, and thus the process is like that.

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A rod of length Lo moves iwth a speed v along the horizontal direction. The rod makes an angle of (θ)0 with respect to the x' ax

Colt1911 [192]

Answer:

From the question we are told that

The length of the rod is $L_o$

The speed is v

The angle made by the rod is $\theta$

Generally the x-component of the rod's length is

$L_x = L_o cos (\theta )$

Generally the length of the rod along the x-axis as seen by the observer, is mathematically defined by the theory of relativity as

$L_xo = L_x \sqrt{1 - \frac{v^2}{c^2} }$

=> $L_xo = [L_o cos (\theta )] \sqrt{1 - \frac{v^2}{c^2} }$

Generally the y-component of the rods length is mathematically represented as

$L_y = L_o sin (\theta)$

Generally the length of the rod along the y-axis as seen by the observer, is also equivalent to the actual length of the rod along the y-axis i.e $L_y$

Generally the resultant length of the rod as seen by the observer is mathematically represented as

$L_r = \sqrt{ L_{xo} ^2 + L_y^2}$

=> $L_r = \sqrt{[ (L_o cos(\theta) [\sqrt{1 - \frac{v^2}{c^2} }\ \ ]^2+ L_o sin(\theta )^2)}$

=> $L_r= \sqrt{ (L_o cos(\theta)^2 * [ \sqrt{1 - \frac{v^2}{c^2} } ]^2 + (L_o sin(\theta))^2}$

=> $L_r = \sqrt{(L_o cos(\theta) ^2 [1 - \frac{v^2}{c^2} ] +(L_o sin(\theta))^2}$

=> $L_r = \sqrt{L_o^2 * cos^2(\theta) [1 - \frac{v^2 }{c^2} ]+ L_o^2 * sin(\theta)^2}$

=> $L_r = \sqrt{ [cos^2\theta +sin^2\theta ]- \frac{v^2 }{c^2}cos^2 \theta }$

=> $L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }$

Hence the length of the rod as measured by a stationary observer is

$L_r = L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }$

Generally the angle made is mathematically represented

$tan(\theta) = \frac{L_y}{L_x}$

=> $tan {\theta } = \frac{L_o sin(\theta )}{ (L_o cos(\theta ))\sqrt{ 1 -\frac{v^2}{c^2} } }$

=> $tan(\theta ) = \frac{tan\theta}{\sqrt{1 - \frac{v^2}{c^2} } }$

Explanation:

7 0

3 years ago

A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below. If the

hodyreva [135]

Vi = 15 m/s
t = 2 s
a = 9.8 m/s^2
y = ?

The kinematic equation that has all of our variables is d = Vi*t + 0.5*a*t^2
y = 15*2 + 0.5*9.8*2^2 = 49.6 m

6 0

2 years ago

How could you make a sound wave sound louder

kykrilka [37]

If you clap your hands, the shock causes the air around your hands to begin vibrating. When air particles vibrate, they bump into other particles near them. Then these particles begin to vibrate and bump into even more air particles. When the air particles begin vibrating the air inside your ear, you hear a sound.

6 0

2 years ago

Did u poop yet friends or do diehra

Dennis_Churaev [7]

Answer:

ummmm none lol

Explanation:

4 0

3 years ago

Sometimes, when the wind blows across a long wire, a low-frequency "moaning" sound is produced. The sound arises because a stand

Crazy boy [7]

Answer:

The smallest integer is n = 4

Explanation:

Using the equation V= Sqrt(F/Linear density)

V= Sqrt(341/0.0120)

V= Sqrt(28416.7)

V= 168.57m/s

Path distance =[ (n +1)/2]lambda

But V= f(Lambda)

n lambda/2 =L

n = f2L/V

n = (20 × 2 × 16.86) / 168.57

n = 4.0007

The smallest integer is n= 4

6 0

2 years ago