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3 years ago

Altuve hits a ball with a bat. The action force is the impact of the bat pushing against the ball. What is the

Physics

2 answers:

prisoha [69]3 years ago

8 0

Answer:

H. The ball pushing on the bat

Explanation:

The question above is related to "Newton's Third Law of Motion." This law states that if an object exerts a force on another object, the second object will exert the same amount of force on the first object but in an "opposite direction." The force exerted by the first object is known as "action force" while the force exerted by the second object is known as "reaction force."

In the situation above, the ball is exerting an "action force on the bat" by pushing the bat. The bat then reacts to its force by pushing it back with an equal force (reaction force) that is opposing it.

Anuta_ua [19.1K]3 years ago

5 0

Answer: H

Explanation: It’s returning the same force back to the bat

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When you do work on a object some of your energy is ________ to that object?

levacccp [35]

When you do work on a object some of your energy is "Transfers" to that object.

Hope this helps!

5 0

3 years ago

Find the net force for 10 N 10 N 25degree 5N 5N

icang [17]

Answer:

30n

Explanation:

7 0

3 years ago

The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in

lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

$\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m$

$\tau=0.5\ N-m$

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

6 0

4 years ago

A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every four days. It is not over that po

Mrrafil [7]

Answer:

106417026.88435 m

Explanation:

T = Time period of the satellite = 4 days

m = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Time period is given by

$T=2\pi\sqrt{\dfrac{r^3}{GM}}\\\Rightarrow r=\left(\dfrac{T^2GM}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=\left(\dfrac{(4\times 24\times 60\times 60)^2\times 6.67\times 10^{-11}\times 5.972\times 10^{24}}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=106417026.88435\ m$

The radius of the satellite's orbit is 106417026.88435 m

5 0

3 years ago

Please help meeeeeeeeeeeeeeeee

Julli [10]

I can't see the answers clearly, but I can see the question. So, I'll just give you a clue/hint.

A stars brightness actually depends on how far it is from your location. If it's far away, it will be dimmer than its counterpart that is closer. To summarize it, if two stars have the same brightness level and one is farther away than the other, the one farther away will appear dimmer than its closer counterpart.

5 0

3 years ago