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allsm [11]
3 years ago
7

What type of movie do men prefer much more than women?

Mathematics
1 answer:
Fofino [41]3 years ago
3 0
C .... i hope I could help and that your staying safe .
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What is the slope for the line that goes through the points?
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Step-by-step explanation:

you follow the graph from the y intercept to the next point

up 2 over 1

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Which person has the lowest ratio of blue to red marbles?
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Hector planted 185 flowers in 2 days.there were 5 volunteers,including Hector, who each planted about the same number of flowers
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The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
2 years ago
(-6,-4), (3,-4) find the slope
V125BC [204]

Answer:

Slope is 9.

Step-by-step explanation: The formula to find slope is m= y2-y1/x2-x1

-6=y1, -4=x1/ 3=y2, -4=x2

3-(-6)/-4-(-4)

=9/0=9

The Slope is 9.

I hope that this has helped, have a good day.

4 0
2 years ago
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