Answer:
0.6944 m/sec^2
Explanation:
The computation of the average acceleration is given below:
a = v - u ÷ t
where
a denotes average acceleration
v denotes final velocity
u denotes initial velocity
t denotes time
So, the average acceleration is
= (25 - 0) ÷ 10
= 0.6944 m/sec^2
maximum allowed value of the speed in roller coaster is given as
![v = 20 m/s](https://tex.z-dn.net/?f=v%20%3D%2020%20m%2Fs)
now from kinematics we can say
![v^2 - v_i^2 = 2 a s](https://tex.z-dn.net/?f=v%5E2%20-%20v_i%5E2%20%3D%202%20a%20s)
here initial speed will be
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
acceleration is due to gravity
![a = 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.8%20m%2Fs%5E2)
now we can use this to find the height
![20^2 - 0^2 = 2 * 9.8* h](https://tex.z-dn.net/?f=20%5E2%20-%200%5E2%20%3D%202%20%2A%209.8%2A%20h)
![400 = 19.6 *h](https://tex.z-dn.net/?f=400%20%3D%2019.6%20%2Ah)
![h = 20.4 m](https://tex.z-dn.net/?f=h%20%3D%2020.4%20m)
so maximum allowed height will be 20.4 m
The force required to slow the truck was -5020 N
Explanation:
First of all, we find the acceleration of the truck, which is given by
![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
where
v is the final velocity
u is the initial velocity
t is the time
For the truck in this problem,
v = 11.5 m/s
u = 21.9 m/s
t = 2.88 s
So the acceleration is
![a=\frac{11.5-21.9}{2.88}=-3.6 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B11.5-21.9%7D%7B2.88%7D%3D-3.6%20m%2Fs%5E2)
where the negative sign means that this is a deceleration.
Now we can find the force exerted on the truck, which is given by Newton's second law:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where
m = 1390 kg is the mass of the truck
is the acceleration
And substituting,
![F=(1390)(-3.6)=-5004 N](https://tex.z-dn.net/?f=F%3D%281390%29%28-3.6%29%3D-5004%20N)
So the closest answer among the option is -5020 N.
Learn more about acceleration and forces:
brainly.com/question/11411375
brainly.com/question/1971321
brainly.com/question/2286502
brainly.com/question/2562700
#LearnwithBrainly
<span>movement of energy through space or a medium Hope this works! ;3</span>