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Lapatulllka [165]
3 years ago
15

Molar mass of Fe2(CO3)3

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
5 0
Use the p table and take 2 times the atomic mass of Fe and then 3 times the atomic mass of C and 9 times the atomic mass of O
So I know that O= 16×9
C=12×3
Fe= Then add all the products up to find molar mass
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Which two celestial bodies orbit the Sun?
tiny-mole [99]
Number 1 is Comets and asteroids
Number 2 is Comets are made of ice and rock
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7 0
3 years ago
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7. Complete the concept map below.
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Drainage that is not handled properly can cause an increase in erosion, changes in stormwater runoff, flooding, and damage to water quality.

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4 0
1 year ago
What were the constraints on Nils Bohlin’s solution to safer seatbelts?
ArbitrLikvidat [17]

Answer:

He realized he needs to have the upper body and lower body held in place and needed the buckle as far down beside the person's hip so it could hold the body properly

Explanation: ''I realized both the upper and lower body must be held securely in place with one strap across the chest and one across the hips,'' Mr. Bohlin once said. ''The belt also needed an immovable anchorage point for the buckle as far down beside the occupant's hip, so it could hold the body properly during a collision.

4 0
3 years ago
An aqueous antifreeze solution is 60.0% ethylene glycol (HOCH2CH2OH) by mass and has a density of 1.06 g/mL. Calculate the molal
galina1969 [7]

Answer:

[HOCH₂CH₂OH] = 24.1 m

Explanation:

Ethylene glycol → HOCH₂CH₂OH

60% by mass means that 60 g of ethylene glycol are contained in 100 g of solution.

Solution mass = Solute mass + Solvent mass

100 g = 60 g + Solvent mass

Solvent mass = 40 g

Molality are the moles of solute contained in 1kg of solvent.

We determine the moles of solute → 60 g . 1mol/62 g = 0.967 moles

We convert the mass of solvent from g to kg → 40 g . 1kg/1000 g = 0.04 kg

Molality → 0.967 mol / 0.04 kg = 24.1 m

4 0
4 years ago
An inexpensive and accurate method of measuring the quantity of electricity flowing through a circuit is to pass the current thr
Paha777 [63]

Total of 127.013 C of charge is passed

Given

 weight of Ag solution before current has passed = 1.7854 g

  weight of Ag solution after current has passed = 1.8016 g

  Molecular mass of Ag = 107.86 g

  Faraday's Constant = 96485

First of all we have to apply Faraday's First Law of Electrolysis i.e

         m = ZQ

  where

Z is propotionality constant (g/C)

Q is charge (C)

Hence,

 Z = Atomic mass of substance/ Faraday's Constant

    = \frac{107.86 g}{96485 C}

    = 0.0011178 g/C

Now ,

   change in mass before and after the passing of current (Δm)

       Δm = 1.8016g-1.7854g

             =   0.0162g

    Now  amount of coulombs passed = \frac{0.142g}{0.0011178 g/C }

          amount of coulombs passed = 127.03524 C

Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C

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7 0
2 years ago
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