No, bleach is not heterogeneous. Bleach is actually homogeneous.
Heterogeneous is if it the same throughout.
Homogeneous is if it is different (has chunks and clumps of different materials)
To answer this question, we will refer to the attached diagram which represents the complete rock cycle.
Rock 1:Formed when rock 2 and rock 3 were subjected to intense heat and pressure inside the earth.
Referring to the diagram, we will find that heat and pressure are the factors required to form metamorphic rocks
Therefore, rock 1 is metamorphicRock 2:Formed when rock 1 and rock 3 were broken down into mineral (sediments) which accumulate and are subjected to pressure.
Referring to the diagram, we will find that this description would lead to the formation of sedimentary rocks.
Therefore, rock 2 is a sedimentary rock.Rock 3:Formed when rock 1 and rock 2 were buried inside the earth and melted because of heat and magma.
Referring to the diagram, we would find that melting then cooling of magma would lead to formation of igneous rock.
Therefore, rock 3 is igneous rock.Based on the above, the correct choice would be:Rock 1: Metamorphic
Rock 2: Sedimentary
Rock 3: Igneous
Answer:a=v-u/t
=23-8/3
=5m/s hope you got your answer
Explanation:
New pressure=3.42 atm
Explanation:
using Boyle's law
P1 V1= P2 V2
P1= initial pressure
V1= initial volume
P2= final pressure
V2=final volume
23.6 (1.52)=P2 (10.5)
P2=3.42 atm
so final pressure= 3.42 atm
The force applied to the second ball by the first ball is 6.734 × 10^-4 N.
<h3>What is impulse of force?</h3>
The impulse of force is defined as the sum of the average force and the duration it is applied.
If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.
Given that: mass of a metal sphere: m = 0.026 kg.
Initial speed of the sphere: u = 3.7 m/s.
When the sphere stops completely, its change in momentum = mu - 0
= 0.026×3.7 N-s.
= 0.0962 N-s.
As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied to the second ball =
change in momentum of 1st ball × time of contact
= 0.0962 × 0.007 N
= 0.0006734 N
= 6.734 × 10^-4 N.
Hence, the force applied to the second ball is 6.734 × 10^-4 N.
Learn more about impulse force here:
brainly.com/question/29787329
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