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svetoff [14.1K]
3 years ago
10

Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generate

d by Lance Armstrong (m = 75.0 kg) is 6.50 W per kilogram of his body mass. (a) How much work does he do during a 189-km race in which his average speed is 12.5 m/s? (b) Often, the work done is expressed in nutritional Calories rather than in joules. Express the work done in part (a) in terms of nutritional Calories, noting that 1 joule = 2.389 x 10-4 nutritional Calories.
Physics
1 answer:
disa [49]3 years ago
3 0

Answer:

E=1760.93 cal

Explanation:

a) First we find the total time

t=x/v

t=189000/12.5

t=15120 seconds

Now we multiply the time by his total wattage

E=t*W

E=(15120)(6.5)(75)=7371000 joules

As,

1 joule = 2.389 x 10-4

So, in term of nutritional Calories

E=7371000 * 2.389*10^{-4}

E=1760.93 Cal

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If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
kaheart [24]

Answer:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

So then the difference of temperature across the material would be \Delta T = 375 K

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

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Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

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If we solve \Delta T in absolute value from the equation (1) we got:

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First we convert 3KW to W and we got:

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And we have everything to replace and we got:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

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Then multiply rad/s^2 by 10 because of the amount of seconds
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