3 years ago

This is a test a b c d e f g h i j k l m n o p

Physics

1 answer:

Tcecarenko [31]3 years ago

5 0

Answer:

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Explanation:

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A hot iron ball of mass 200 g is cooled to a temperature of 22°C. 6.9 kJ of heat is lost to the surroundings during the process.

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Heat lost or gained, H = mc(θ₂ - θ₁)
Where m = mass, c = Specific heat capacity, θ₂= final temperature, θ₁ = initial temperature

m = 200g, c = 0.444 J/g°C, θ₁ = 22 °C (Since it was cooled).

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So initial temperature before cooling ≈ 100°C . Option C.

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