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Mkey [24]
3 years ago
11

What is the valence of K2O2

Chemistry
1 answer:
raketka [301]3 years ago
6 0
14 since K has 1 valence but there’s two so 2 valence for k and oxygen has 6 but there’s two so 12
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What units are used in the periodic table for atomic mass?
AleksAgata [21]
D. amu
amu stands for atomic mass unit
5 0
3 years ago
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A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?
kotykmax [81]
First M stands for Molarity which is (moles of solute) / (Liters of solution). we also know that moles = (mass) / (molar mass). so we can form some equations here. We know:
Molarity (M) = moles (mol) / Liters (L)
moles (mol) = (mass) / (molar mass)

we can substitute the (mass) / (molar mass) for (moles) and get:
M = [(mass) / (molar mass)] / Liters

we can now isolate mass and get
M * Liters * molar mass = mass

now we need to find the molar mass of CaCl2 which is 110.98 g/mol

plug the values in and get
.350M * 6.5L * 110.98 g/mol = mass

mass = 252.4795g however the 6.5L has only 2 sig figs so i would say

mass CaCl2 = 2.5 * 10 ^2 g
5 0
3 years ago
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Lymph nodes are...
MrMuchimi

Answer:

a

Explanation:

7 0
3 years ago
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ladessa [460]

Answer:

B

Explanation:

because it is being cooled down

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3 0
2 years ago
Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point
xeze [42]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

Explanation:

Elevation in boiling point:

\Delta T_b=i\times k_b\times m

where,

\Delta T_b = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

k_b = boiling point constant = 2.53^0C/kgmol

m = molality = 3.70

T_{solution}-T_{solvent}=i\times k_b\times m

T_{solution}-80.1^0C=1\times 2.53\times 3.70

T_{solution}=89.5^0C

Thus  the boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

8 0
3 years ago
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