Answer:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Explanation:
The silver nitrate, AgNO₃, dissolves in water as follows:
AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)
The Ag⁺ reacts with Cl⁻ producing AgCl(s), a white insoluble salt. The net ionic equation that describes the formation of the precipitate is:
<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 /><h3 />
The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
<h3>What is current?</h3>
The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
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Answer: Look it up on the internet
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Answer:
I am not really sure, but I think Fr.
Explanation: