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3 years ago

You want to prevent charges from moving off of a charged metal sphere.

Physics

2 answers:

ZanzabumX [31]3 years ago

5 0

B. It has a high resistance and is an insulator.

Explanation:

To prevent charges from moving off of a charged metal sphere, it is best to use a material with a high resistance and is an insulator.

An insulator is a substance that does not allow electric charges and currents to move through.
A material of high resistance retar/ds the flow of electricity.
An insulator is therefore a material with a very high resistance.
This will not allow electric current to pass through.
To prevent movement of charges, we thereby use insulators.
Conductors on the other hand are materials that allows electric charges to pass through.
They generally have low resistance.

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Metals brainly.com/question/2474874

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Veronika [31]3 years ago

3 0

Answer: it has a high resistance and is an insulator

Explanation:

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An airplane flies 20km in a direction 60 degrees north of east, then 30 km straight east, then 10km straight north. How far and

Fed [463]

Answer:

48.4 km, 34.3° north of east

Explanation:

Let's say east is the +x direction and north is the +y direction.

Adding up the x components of the vectors:

x = 20 cos 60 + 30 + 0

x = 40 km

Adding up the y components of the vectors:

y = 20 sin 60 + 0 + 10

y = 27.3 km

The magnitude of the displacement is:

d = √(x² + y²)

d = 48.4 km

The direction is:

θ = atan(y/x)

θ = 34.3° north of east

6 0

3 years ago

One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe

Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

$\mu = \frac{m}{l}$

$\mu = \frac{8.79*10^{-3}}{70*10^{-2}}$

$\mu = 0.01255kg/m$

The expression for the wavelength of the standing wave for the second overtone is

$\lambda = \frac{2}{3} l$

Replacing we have

$\lambda = \frac{2}{3} (70*10^{-2})$

$\lambda = 0.466m$

The frequency of the sound wave is

$f_s = \frac{v}{\lambda_s}$

$f_s = \frac{344}{0.768}$

$f_s = 448Hz$

Now the velocity of the wave would be

$v = f_s \lambda$

$v = (448)(0.466)$

$v = 208.768m/s$

The expression that relates the velocity of the wave, tension on the string and linear mass density is

$v = \sqrt{\frac{T}{\mu}}$

$v^2 = \frac{T}{\mu}$

$T= \mu v^2$

$T = (0.01255kg/m)(208.768m/s)^2$

$T = 547N$

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the $n^{th}$ harmonic frequency is

$f_n = nf_1$

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

$n=3$

Then,

$f_3 = 3f_1$

Rearranging to find the fundamental frequency

$f_1 = \frac{f_3}{3}$

$f_1 = \frac{448Hz}{3}$

$f_1 = 149.9Hz$

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olga55 [171]

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Harlamova29_29 [7]

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bija089 [108]

Cathode rays are negatively charged

Explanation:

Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.

Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.

One notable one was that he observed that the rays deflected towards the positively charged plate.

Since unlike poles attract then he concluded that the cathode rays were negatively charged.

learn more:

Rutherford brainly.com/question/1859083

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3 years ago