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Sophie [7]
4 years ago
15

You want to prevent charges from moving off of a charged metal sphere.

Physics
2 answers:
ZanzabumX [31]4 years ago
5 0

B. It has a high resistance and is an insulator.

Explanation:

To prevent charges from moving off of a charged metal sphere, it is best to use a material with a high resistance and is an insulator.

  • An insulator is a substance that does not allow electric charges and currents to move through.
  • A material of high resistance retar/ds the flow of electricity.
  • An insulator is therefore a material with a very high resistance.
  • This will not allow electric current to pass through.
  • To prevent movement of charges, we thereby use insulators.
  • Conductors on the other hand are materials that allows electric charges to pass through.
  • They generally have low resistance.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

Veronika [31]4 years ago
3 0

Answer: it has a high resistance and is an insulator

Explanation:

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The area around a charged object that can exert a force on other charged objects is an electric ___
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Answer is:

Electric field.
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3 years ago
Please help on this one?
kupik [55]

Answer: A)30V. First find the current of the circuit. I=V/R(total resistance). So I=60/120=0.5. Now to find voltage drop in R3 use ohms law as given. V(of 3)=(0.5)(60)=30V

7 0
3 years ago
A sphere of radius R contains charge Q spread uniformly throughout its volume. Find an expression for the electrostatic energy c
tensa zangetsu [6.8K]

Answer:

E = \frac{3kQ^2}{5R}

Explanation:

Let the sphere is uniformly charge to radius "r" and due to this charged sphere the electric potential on its surface is given as

V = \frac{kq}{r}

now we can say that

q = \frac{Q}{\frac{4}{3}\pi R^3} (\frac{4}{3}\pi r^3)

q = \frac{Qr^3}{R^3}

now electric potential is given as

V = \frac{k\frac{Qr^3}{R^3}}{r}

V = \frac{kQr^2}{R^3}

now work done to bring a small charge from infinite to the surface of this sphere is given as

dW = V dq

dW = \frac{kQr^2}{R^3} dq

here we know that

dq = \frac{3Qr^2dr}{R^3}

now the total energy of the sphere is given as

E = \int dW

E = \int_0^R  \frac{kQr^2}{R^3} (\frac{3Qr^2dr}{R^3})

E = \frac{3kQ^2}{R^6} (\frac{R^5}{5} - 0)

E = \frac{3kQ^2}{5R}

7 0
4 years ago
Which would most likely cause specular reflection? O a pathway with rough rocks a shiny, smooth leaf a small patch of soil a rou
andrew11 [14]

Answer:

a shiny smooth leaf

Explanation:

A shiny smooth leaf will cause specular reflection. Other choices will cause diffused reflection from the surface.

A specular reflection is similar to how a mirror or smooth surface reflects. The incident light is given off as a single ordered reflection from the surface of a body.

For this to occur, the surface incident must be smooth and without rough patterns on it.

A path way with rough rocks, small patch of soil and rough logs will give off diffused reflection

8 0
3 years ago
Read 2 more answers
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