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Iteru [2.4K]
3 years ago
5

What is the wavelength in nm of a light whose first order bright band forms a diffraction angle of 30 degrees, and the diffracti

on grating has 700 lines per mm? ​
Physics
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:

The wavelength is 3500 nm.

Explanation:

d= \frac{1}{700 lines per mm} = 0.007mm = 7000 nm

n= 1

θ= 30°

λ= unknown

Solution:

d sinθ = nλ

λ = \frac{7000 nm sin 30}{1}

λ = 3500 nm

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m\frac{v^2}{r}=\frac{GMm}{r^2}\\\Rightarrow \frac{\left(\frac{2\pi \times r}{24\times 3600}\right)^2}{r}=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{r^2}\\\Rightarrow \left(\frac{2\pi \times r}{24\times 3600}\right)^2=6.667\times 10^{-11}\times 5.98\times 10^{24}\\\Rightarrow r^3=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\\\Rightarrow r=\left(\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42244138.951\ m

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