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3 years ago

8

A transverse wave causes its medium to move in what direction?

2 answers:

Mariulka [41]3 years ago

8 0

Answer:

Explanation:

A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down.

Svetllana [295]3 years ago

4 0

Answer:

many directions

Explanation:

A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down.

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Which option determines gravitational pull? the Sun <br>volume <br>mass <br>acceleration

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Mass
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3 years ago

Any help is appreciated

sdas [7]

image distance,di=10 cm

object distance,do=20cm

magnification, m=di/do

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3 years ago

A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler

Tema [17]

Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(525\ m/s)^2}{5200\ m}$

$a=53.004\ m/s^2$

We know that, the value of g is, $g=9.8\ m/s^2$

$\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4$

$a=5.4\times g$

So, the acceleration of the plane is 5.4 g. Hence, this is the required solution.

6 0

3 years ago

Read 2 more answers

A toy rocket moving vertically upward passes by a 2.0-m-high window whose sill is 8.0 m above the ground. The rocket takes 0.15

sveta [45]

Answer:

$v_i = 18.86 m/s$

Explanation:

As we know that the speed of the rocket is v1 and v2 at the bottom and top of the window

then we will have

$d = (\frac{v_1 + v_2}{2}) t$

$2 = (\frac{v_1 + v_2}{2})(0.15)$

$26.67 m/s = v_1 + v_2$

also we know that

$v_2 - v_1 = (-9.81)(t)$

$v_2 - v_1 = (-9.81)(0.15) = -1.47$

now we have

$v_2 = 12.6$

also we have

$v_1 = 14.1 m/s$

now if the sill of the window is at height 8 m from the ground then we have

$v_1^2 - v_i^2 = 2 a h$

$(14.1^2) - v_i^2 = 2(-9.81)(8)$

$v_i = 18.86 m/s$

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A girl is walking a dog. The tension force applied to the dog is 20 N. If the mass of the dog is 25

Mrac [35]

Umm what’s the question

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3 years ago