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3 years ago

Measurements made by a caliper can be read from a dial gage, a digital display, or a

1 answer:

7 0

<span> vernier scale because is a part of vernier calipers.rest of them are parts of other measuring instruments like dial guage, screw guage etc</span>

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Which statement is true? *

never [62]

The last paragraph is the correct statement. Please don't make me type it all out.

6 0

4 years ago

Read 2 more answers

Rahul runs a distance of 12

Radda [10]

Answer:

Rita runs faster

Explanation:

To obtain the answer to the question given, we determine the speed of Rita. This can be obtained as follow:

Distance = 1.6 km

Time = 15 mins

Speed =?

Next, we shall convert 15 mins to hour. This can be obtained as follow:

60 mins = 1 h

Therefore,

15 mins = 15 mins × 1 h / 60 mins

15 mins = 0.25 h

Thus, 15 mins is equivalent to 0.25 h.

Finally, we shall determine speed of Rita as follow:

Distance = 1.6 km

Time = 0.25 h

Speed =?

Speed = distance / time

Speed = 1.6 / 0.25

Speed = 6.4 Km/h

Thus Rita's speed is 6.4 Km/h

Comparing the speed of Rahul and Rita

Rahul's speed = 4.5 km/h

Rita's speed = 6.4 Km/h

We can see that Rita's speed is greater than Rahul's speed. This simply indicates that Rita runs faster than Rahul.

4 0

3 years ago

Newton's Law of Cooling states that the rate of cooling of an object is proportional to the temperature difference between the o

julsineya [31]

Answer:

1) $k=-\frac{1}{46}\approx -0.02$

2) $\textit{Limiting value} = 24$

3) $T(10)\approx \frac{494611944}{6436343}\approx 76.8$

Explanation:

First of all note that

$T_s=24$ is the surroundings temperature, the temperature of the room where the cup of coffee is. Then, the differential equation is:

$\frac{dT}{dt}=k(T-24)$

Also, note that all units are in degrees celsius and minutes. Then, we don't have to convert units. Let's not write units explicitly from now on.

Explanation

1) We have that

$\textit{rate of cooling}=\frac{dT}{dt}=1,\quad T=70$

at some point - the exact time at which this is true doesn't really play any role because the equation doesn't have t on the right hand side. Then, from the equation we get

$1=-(70-24)=46k\Rightarrow k=-\frac{1}{46}\approx -0.02$

The minus comes from considering the temperature must decrease. With this value we can write the equation more explicitely:

$\frac{dT}{dt}=-\frac{1}{46}(T-24)$

2) The coffee is cooling off as time goes by, and it won't get any cooler than 24 degrees celsius because that's the temperature of the room. Then, in the long run, the temperature of the coffee is 24 degrees celsius.

3) Remember that Euler's method consists of using an initial exact measurement to predict what will happen in the future, approximately. There is a formula to make those predictions an it depends on the time step they gave us. Let's compute things first and then I tell you the equations we used.

In this case we know that we start with a 90 degrees celsius cup of coffee, or, in terms of math,

$T(0)=90$

Then, we can predict:

$T(2)\approx 90+2\left[-\frac{1}{46}(90-24)\right]=\frac{2004}{23}\approx 87.1$

Let's use fractions so we don't lose accuracy from now. With this number we can make an approximation of the temperature after 2 more seconds:

$T(4)\approx \frac{2004}{23}+2\left[-\frac{1}{46}\left(\frac{2004}{23}-24\right)\right]=\frac{44640}{529}\approx 84.4$

and then

$T(6)\approx \frac{44640}{529}+2\left[-\frac{1}{46}\left(\frac{44640}{529}-24\right)\right]=\frac{994776}{12167}\approx 81.8$

and then

$T(8)\approx \frac{994776}{12167}+2\left[-\frac{1}{46}\left(\frac{994776}{12167}-24\right)\right]=\frac{22177080}{279841}\approx 79.2$

and finally, the number we wanted to find:

$T(10)\approx \frac{22177080}{279841}+2\left[-\frac{1}{46}\left(\frac{22177080}{279841}-24\right)\right]=\frac{494611944}{6436343}\approx 76.8$

I hope you noticed the pattern to compute the next prediction:

$\textit{next prediction} = \textit{previous one (or exact value if it's the first step)}\\+ h\ast(\textit{right hand side of the differential equation at the previous one})$

5 0

3 years ago

An object of height 8.50 cm is placed 20.0 cm to the left of a converging lens with a focal length of 12.0 cm. Determine the ima

ddd [48]

The image distance is 33.3 cm while the image height is 14.2 cm.

<h3>What is a converging lens?</h3>

A converging lens will always have a positive focal length hence, we have to find the object distance as follows;

1/f = 1/v + 1/u

1/12 = 1/v + 1/20

1/v = 1/12 - 1/20

1/v = 0.08 - 0.05

v =33.3 cm

Now;

Magnification = 33.3 cm/20.0 cm =1.67

M = Image height/Object height

1.67 = Image height/8.50 cm

Image height = 1.67 * 8.50 cm

Image height = 14.2 cm

Learn more about focal length:brainly.com/question/16188698

#SPJ1

5 0

2 years ago

Give two examples of gravity in the solar system

Nikolay [14]

The planets revolving around the sun, The moon revolving around the Earth.

6 0

3 years ago