Answer:
F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.
Explanation:
Answer: 2859.78 k
Explanation: By using the law of conservation of energy, the kinetic energy of the meteor equals the heat energy.
Kinetic energy = 1/2mv^2
Heat energy = mcΔθ
Where m = mass of meteor , v = velocity of meteor = 1623 m/s
c = specific heat capacity of meteor (iron) = 460.548 j/kg/k
Δθ = change in temperature of meteor = ?
From law ofconservation of energy, we have that
1/2mv^2 = mcΔθ
By cancelling "m" on both sides, we have that
v^2/2 = cΔθ
v^2 = 2cΔθ
(1623)^2 = 2× 460.548 × Δθ
2634129 = 921.096 × Δθ
Δθ = 2634129 / 921.096
Δθ = 2859.78 k
Answer:
The same.
Explanation:
Temperature is a measure of the average kinetic energy of a substance; if two pieces of iron have the same temperature, then their particles will have the same amount of average kinetic energy.
Answer:
A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)
Explanation:
<u>To rank the angular speed (ω) of the objects, we need first calculate its value for every object:</u>
A bowling ball of radius 12.3cm rotating at 8.21 radians per second:
ω = 8.21 rad/s
A tire of radius 0.321m rotating at 75.8 rpm:
A 6.84cm diameter top spinning at 375 degrees per second:
A square with sides (b) 0.458m long, whose corners are moving with tangential speed (v) 2.51 m/s as it rotates about its center:

A rock on a string, being swung in a circle of radius 0.521 m with a centripetal acceleration (a) of 25.4 m/s²:
<u>Now, the rank of the angular speed of the objects, from highest to lowest is: </u>
A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)
I hope it helps you!
Answer:
145.8 cm³ of paint
Explanation:
d₁ = Smaller diameter paintball = 5 cm
d₂ = Larger diameter paintball = 9 cm
V₂ = Volume of larger diameter paintball
Volume of smaller diameter paintball

Similarly

Dividing the above two equations, we get

∴ The larger one hold 163.296 cm³ of paint