Answer:
(3R,4R)-4-bromohexan-3-ol
Explanation:
In this case, we have reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.
Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)
I hope it helps!
Answer:
Watch the attached image, please.
Explanation:
To complete the Lewis structure for this covalent compound, you have to draw all the atoms with their valence electrons.
The drew has the nitrogen in the center and the fluoride and oxygen in the sides.
Each one of these atoms has to complete the octet rule, which is the ruler who says that all the atoms want to reach to have eight electrons to feel "stable".
For that reason, you have to arrange the atoms to comply with this rule.
Answer:
halogens
Explanation:
on a periodic table (just search ptable.com) right under the 17 in small words it says halogens
0.1 Centigrams Per Milliliter.
Always check the results; rounding errors may occur.